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Aptitude Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Aptitude. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
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Q 1 - Two train approach one another at 30 km/hr and 27 km/hr from two spot 342 km separated. After how long will they meet?
Answer : B
Explanation
Suppose the two trains meet after x hours. Then, 30x+27 x= 342 ⇒ 57 x = 342 ⇒ x = 342/57 = 6. So the two trains will meet after 6 hours.
Q 2 - If 5 men or 9 ladies can complete a bit of work in 19 days, 3 men and 6 ladies will do likewise work in
Answer : D
Explanation
5 men 1 day work = 1/19 ⇒ 1 man's 1 day work = 1/95 9 women 1 day work = 1/19 ⇒1 women 1 day work = 1/171 (3 men + 6 women) 1 day work = (3/95 + 6/171) = (27+30)/855 = 57/ 855 = 1/15 ∴ 3 men and 6 women can finish the work in 15 days.
Answer : C
Explanation
given exp. = (3/2) / 1+ 1(/5/4) = (3/2)/ (1+4/5) = (3/2) /(9/5) = ( 3/2 * 5/9) = 5/6
Q 4 - Sum of two numbers is 60 and their H.C.F and L.C.M are 12 and 72 respectively. One of the numbers is:
Answer : B
Explanation
Let the numbers be 12 a and 12 b, where a and b are co primes. Then, 12 a *12 b = 12 *72 ⇒ ab= 6 co-primes with product 6 are a = 2, b= 3 ∴ numbers are (12*2, 12*3 ) i.e 24 and 36
Q 5 - 12 + 22 ... + x2 = [x(x+1)(2x+1)]/6. What is 12 + 32 +... + 202?
Answer : A
Explanation
(12 + 32 ... + 202) = (12 + 22 ... + 202) - (22 + 42 ... + 192) Using formula (12 + 32 ... + n2) = [n(n+1)(2n+1)]/6 [20(20+1)(40+1)]/6 - (1 x 22 + 22 x 22 + 22 x 32 + ... + 22 x 92 + 22 x 102) = 2870 - 22(12 + 22 + ... + 192) = 2870 - 4(1 x 2 x 39)/6 = 2870 - 52 = 2818
Q 6 - The average age of five officers in a department is 32 years. If the age of their supervisor is added the average increases by 1. What is the supervisor's age?
Answer : C
Explanation
Supervisor?s age = 32 + 6 = 38 years
Q 7 - If the true discount on sum due 3 years hence at 10% per annum be Rs. 180, the sum due is
Answer : A
Explanation
Present worth=( 100*TD)/R*T=( 100 *180 )/10*3=Rs.600.
Q 8 - The two hands of a clock will be together between h and (h+1) o'clock at
A - (60/11)h minutes past h o' clock
B - (50/11)h minutes past h o' clock
Answer : A
Explanation
At h o' clock, the minutes hand is 5 h minute spaces behind the hour hand. The minute hand gains 55 min spaces in 60 mins. ∴ The minute hand will gain 5h minute spaces in 60/55 * 5h = 60h/11 minutes. ∴ The two hands will be together between 'h' and 'h+1' o' clock at (60/11)h minutes h o' clock.
Q 9 - Ajay , Bijender and chaman started a business and invested Rs. 20000 each partner .After the period of 4 month, some changes are made in investment just like Ajay withdraw Rs. 5000, Bijender and chaman both add 6000 each in the invested capital. An amount of Rs. 69900 recorded as a profit in the firm. What should be the share of Bijender in profit?
Answer : B
Explanation
Ajay : Bijender: chaman = (20000*5+15000*7) : (20000*5+ 16000*7) :(20000*5+26000*7) = 205000: 212000 : 262000 = 205 : 212: 282 Share of B in profit = Rs. (69900* 212/699) = Rs. 21200
Q 10 - The aggregate surface territory of a strong barrel is 231 cm2. On the off chance that its bended surface zone is two ?third of its aggregate surface zone, then its Volume is:
Answer : A
Explanation
(2πrh+2πr2) =231 and 2πrh= 2/3*231= 154 ∴154+ 2πr2 =231 ⇒2*22/7*r2= (231-154) =77 ⇒r2 = (77*7/44)= 49/4 ⇒ r =7/2 cm ∴2*22/7*7/2*h= 154 ⇒ h= 7cm ∴ Volume = πr2h = (22/7 *7/2 * 7/2 * 7) cm3 = 539/2 =269.5 cm3