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Aptitude - Arithmetic Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - Which term of 2,7, 12,17... is 87?

Answer : C

Explanation

  
Here a = 2,  d = 7 - 2 = 5,  
Let there be n term.  
Using formula T_n = a + (n - 1)d  
T_n = 2 + (n - 1) x 5 = 87  
=> 5n - 3 = 87  
=> n = 18

Q 2 - The divisor is five times the quotient and five times the remainder. If the remainder is 29, the dividend is?

Answer : B

Explanation

  
Divisor = (5 x 29) = 145 = 5 x Quotient = Divisor 
=> Quotient = 145/5 = 29 
Dividend = (Divisor x Quotient) + Remainder 
Dividend = (145* 29) + 29 = 4234.

Q 3 - The sum of first 99 natural numbers is?

Answer : D

Explanation

  
 Sum of n natural numbers is  S_n=n(n+1)/2  =99(99+1)/2  
 =4950

Q 4 - If the sum of four consecutive even numbers is 228, which is the smallest of the numbers?

Answer : B

Explanation

  
 According to the question:       
 x + x + 2 + x + 4 + x + 6 = 228  
 or, 4x + 12 = 228  
 or, x = 54  
 ∴The least even number is 54.

Q 5 - How many numbers between 100 and 200 are exactly divisible by 6 and 9?

Answer : B

Explanation

 
 L.C.M. of 9 and 6 = 18 
 ∴ required numbers are 108, 126, 144, 162, 180, 198 which are 6.

Q 6 - What is the sum of first 20 odd numbers?

Answer : C

Explanation

 
 Here numbers are 1, 3, ..., upto 20 terms which is an A.P. Here a = 1,  d = 2, n = 20. 
 Now Using formula S_n = (n/2)[2a + (n-1)d]  
 ∴ Required sum = (20/2)[2+(20-1)x2]  = 10 x 40  = 400

Q 7 - Which term of 5, 10, 20, 40,.... is 1280?

Answer : B

Explanation

  
 Here numbers are in G.P.  Here a = 5,  r = 2, l = 1280. 
 Using formula T_n = ar^{n- 1} 
 T_n = 5 x 2^(n-1) = 1280  
 =2^(n-1) = 256  
 =2^(n-1) 
 = 2⁸  
 => n - 1 = 8  => n = 9

Q 8 - One has to pay 3600 in 40 installments which are in A.P. After 30th installment being paid, amount left will be one third. What will be the 8^th installment?

Answer : C

Explanation

   
 Installments = 40, Total debt = 3600  Installments = 30, 
 Total debt = (2/3) x 3600 = 2400  
 Let the installments be a, a + d, a + 2d, ...  
 Using formula S_n = (n/2)[2a+(n-1)d]   
 S₃₀ = (30/2)[2a+(30-1)d] = 3600  
 => 2a + 29d = 160 ... (i)  
 S₄₀ = (40/2)[2a+(40-1)d] = 2400  
 => 2a + 39d = 180 ... (ii)  
 Subtracting (i) from (ii)  
 => 10d = 20  
 => d = 2  
 Using (i)  2a = 160 - 29d = 160 - 58 = 102  
 => a = 51  
 Using formula T_n = a + (n-1)d  
 ∴ T₈ = 51 + 7 x 2 = 51 + 14  = 65

Q 9 - What is y if 2y, y+10, 3y+5 are in an A.P.?

Answer : B

Explanation

    
 As numbers are in A.P.  Thus (y + 10) - 2y = (3y + 5) - (y + 10)  
 => 10 - y = 2y - 5  
 => -3y = -15  
 => y = 5

Q 10 - How many 2 digits numbers are there which are divisible by 6?

Answer : B

Explanation

  
 Here series is 12, 18, 24, ... 96.  
 Here a = 12,  d = 18 - 12 = 6     
 Using formula T_n = a + (n - 1)d     
 T_n = 12 + (n - 1) x 6 = 96     
 => 12 + 6n - 6 = 96    
 => 6n = 90  
 => n = 15

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