![Quantitative Aptitude Tutorial](/quantitative_aptitude/images/aptitude-mini-logo.jpg)
- Aptitude Test Preparation
- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
- Aptitude Useful Resources
- Aptitude - Questions & Answers
Aptitude - Percentages Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Percentages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
![Questions and Answers](/images/questions_and_answers.png)
Answer : B
Explanation
= (45⁄100 x 750) - (25⁄100) x 480) = 337.50 - 120 = 217.50
Q 2 - The difference between a number and its two-fifth is 510. What is 10% of that number?
Answer : D
Explanation
Let p be the number. Then, p - 2⁄5 p = 510 p = 850, 10% of 850 = 85
Q 3 - In an examination, 35% of the students passed and 455 failed. How many students appeared for the examination?
Answer : A
Explanation
Let s be the number of students appeared for the examination. Then, 65% of s = 455 i.e. 65⁄100s = 455 Therefore, Students = 700
Answer : D
Explanation
→ Z% of Z = 36 Therefore, (Z⁄100)x Z = 36 Z = 60
Q 5 - The monthly salary of Abdul is Rs 60000. He spend 20% of it on the education of his children, 25% on house rent, 5% on travels, 30% on food, 8% on miscellaneous items and rest he saves for the future. Find his savings.
Answer : B
Explanation
Total expenditure = (20 + 25 + 5 + 30 +8)% = 88% Savings = 100% - 88% = 12% => His savings = 12/100 * 60000 = 7200
Q 6 - The population of a state is counted after every three years. It is found that the population each time is increased by 20% as compared to the previous count. If the population in the year 1998 was 42 lakhs, what will be the population in the year 2007 in lakhs?
Answer : B
Explanation
Since population is counted after every three years, there will be three countings between 1998 and 2007. ∴ Population in 2007 = 42(1 + 20/100)3 = 42(6/5)3 = 42 (216/125) = 72.576 lakhs
Q 7 - In an election the losing candidate gets 20% of the votes polled is defeated by 12000 votes. The number of votes polled by winning candidate is
Answer : C
Explanation
Let the votes polled by the winning candidate be x, then (x-12000) =20%of (x+(x-12000)) x=16000
Q 8 - The price of rice is increased by 10 %.If the expenditure is not allowed to increase , the ratio between the reduction in consumption and the original consumption is
Answer : D
Explanation
Reduction in consumption = 10/110*100=100/11% (reduction in consumption)/(original consumption) = 100/11*1/100=1/11=1:11
Answer : D
Explanation
(9% of 386) * (6.5% of 144) = 347.4 - 93.6 = 253.8
Q 10 - If the radius of a circle is increased by 4 times, what will be the percentage increase in its area?
Answer : D
Explanation
Area of circle = Πr2 Area of new circle = Π(4r2) = 16Πr2 = 16 times the area of the original circle ∴ Required percentage = (16 – 1)/1 * 100 = 1500%