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Area Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A rectangle measures 8cm on length and its slanting measures 10 cm. what is the border of the rectangle?
Answer : C
Explanation
second side = √{(10)2-(8)}2= √(100-64) =√36= 6cm
Perimeter = 2(8+6) = 28cm
Q 2 - The askew of a square is 4√2cm. the inclining of other who?s Range is twofold that of the first square is:
Answer : A
Explanation
Area of given square = 1/2 (diagonal) 2= {1/2 (4√2) 2} cm2=16cm2
Area of new square = (2*16) cm2 =32cm2
Let the diagonal of 2nd square be D cm
Then, 1/2*D2=32 ⇒D2=64 ⇒D=8 cm
Q 3 - The length of a rectangular plot is expanded by 25%. To keep its region unaltered, the width of the plot ought to be:
Answer : D
Explanation
Let the length be x meter and breadth be y mtr. Then, its area = (xy) m2 New length = (125/100*x) m = (5x/4) m. let the new breadth be z meters. Then, xy = 5x/4*z ⇒z= 4/5 y Decrease in width = (y-4/5y) = y/5 mtr. Decrease % in width = (y/5*1/y*100) % = 20%
Q 4 - A Verandah 40m long and 15 m wide is to be cleared with stones every measuring 6dm by 5dm. The quantity of stones required is:
Answer : B
Explanation
Area of the verandah= (40*15)m2= 600m2 Area of one stone= (6/10*5/10) m2= 3/10m2 No. of stones = (600*10/3) = 2000
Q 5 - The perimeter of a square circumscribed about a circle of radius r is:
Answer : C
Explanation
Each side of the square = 2r ∴ Perimeter of the square = (4* 2r) = 8r.
Q 6 - The ratio of the area of a square of side a and that of an equilateral triangle of side a, is
Answer : D
Explanation
Required ratio = a2/(√3/4) a2 = 4/√3= 4:√3
Q 7 - The areas of two similar triangles are 12 cm2 and 48 cm2 .If the height of the smaller one is 2.1 cm, then the corresponding height of the bigger one is:
Answer : B
Explanation
The areas of two similar triangles are in the ratio of the square of the corresponding sides. ∴12/48= (2.1)2/h2 ⇒h2=4* (2.1)2 ⇒h= (2* 2.1) = 4.2 cm
Q 8 - The territory of a circle engraved in an equilateral triangle is 462 cm2. The edge of this triangle is:
Answer : C
Explanation
Πr2 = 462 ⇒ 22/7* r2 = 462 ⇒ r2 = (462*7/22) = 147 ⇒ r = √ 7*7*3 = 7 √3 cm Height = 3r = (3* 7 √ 3) cm = 21√ 3 cm a2 - (a/2) 2 = (21√ 3) 2 ⇒ (a2- a2/4) = 1323 3a2 = (1323*4) ⇒ a2= (441* 4) ⇒ a = (21*2) = 42 Perimeter of the triangle = 3a = (3*42) = 126 cm.
Q 9 - The border of a rhombus is 52cm and the length of its littler Inclining is 10cm. The length of the more extended slanting is:
Answer : D
Explanation
Each side = 52/4=13cm Let AC be the smaller diagonal, Then AC= 10cm Let AC and BD intersect at o. Then ∠AOB= 90∘ and AO= 1/2 AC= 5cm In right ∆ AOB, we have AB= 13cm, AO=5cm ∴ OB =√ (ab) 2-(OA) 2= √ (13)2-(5)2= √169-25 =√144=12cm ∴ BD =2*BO= (2*12) =24 cm
Q 10 - A round greenery enclosure has an outline of 440 m. There is a 7m wide fringe inside the patio nursery along its outskirts. The territory of the fringe is:
Answer : D
Explanation
2πR =440 ⇒ 2*22/7*R= 440 ⇒R= (440* 7/44)=70 m Outer radius = 70m, inner radius = (70-7) =63 m Required area = π [(70)2-(63)2] m2= 22/7 *(70+63) (70-63) m2 = (22*133) m2, = 2926m2
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