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Aptitude - Simple Interest Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Rs 6000 get to be Rs 7200 in 4 years at a sure rate of interest. On the off chance that the rate gets to be 1.5 times of itself, the measure of the same central in 5 years will be:
Answer : B
Explanation
S.I on Rs 6000 for 4 years= (7200-6000) = 1200 Rs. ∴ Rate = (100*1200/6000*4) % p.a. = 5% p.a New rate = (5*3/2) % = 15/2% P.a. Required amount = [6000+ (6000*5/100*15/2)] = Rs. (6000+2250) = Rs. 8250.
Q 2 - The total of cash that will give Re 1 as basic premium for each at the rate of 5% for every annum is:
Answer : C
Explanation
Annual interest = Rs. 365, Rate = 5% p.a. Sum = (100*S.I/R*T) = Rs. (100*365/5*1) = Rs. 7300.
Q 3 - In the event that the yearly rate of simple interest increments from 10% to 25/2 %, a man yearly pay increments by Rs 1250. The primary is:
Answer : C
Explanation
Let the principle be rs. x. Then, (x* 25/2*1/100*1)- (x*10/100*1) = 1250 => x/8 ?x/10 = 1250 => 5x- 4x= 50000 X= 50000. Hence, the principle is Rs. 50000.
Q 4 - A man loses Rs 55.50 yearly when the yearly rate of interest tumbles from 11.5% to 10%. His capital is:
Answer : A
Explanation
Let the capital be Rs. x. then, (x*23/2*1/100*1) ?(x*10*1/100*1) = 55.50 => 23x/200 ?x/10 =111/2 => 23x-20x =11100 => 3x= 11100 => x = 3700 Hence, the capital is Rs. 3700.
Q 5 - A man disperses Rs. 25300 among his three children A, B, C. In a manner that the measure of there at 10% simple interest for a long time, 3 years and 4 years will be equivalent an offer is:
Answer : C
Explanation
Let the parts of A, B, C be x, Y, z respectively. Then (x+ x*2*10/100)= (Y+ y*3*10/100) = (z+ z*4*10/100) => 6x/5 =13y/10 = 7z/5 =ℏ = 5ℏ/6, y = 10ℏ/13, z= 5ℏ/7 => x: y: z = 5ℏ /6:10ℏ/13 :5ℏ/7 = 1/6:2/13: 1/7 = 91: 84: 78 A's part = Rs. (25300*91/253) = Rs. 9100.
Q 6 - A sum of Rs 1500 is lent out in two parts in such a way that the simple interest on one part at 10% per annum for 5 years is equal to that on another pert at 12.5% per annum for 4 years. The sum lent out at 12.5% is:
Answer : C
Explanation
Let the sum lent out at 12.5% be x Sum lent out at 10% = 1500 - x Now, (1500-x)*10*5/100 = x * 12.5*4/100 Or, 50(1500-x) = 50x Or, 2x = 1500 Or, x = 750
Q 7 - A sum of money lent out at simple interest amounts to RS. 720 after 2 years and to 1020 after a further period of 5 years. The sum is?
Answer : B
Explanation
S.I. for 5 year = Rs. (1020 - 720) = 300 S.I. for 2 years = Rs. (300 x 2⁄5) = 120 Therefore Principal = (720 - 120) = 600
Q 8 - A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Answer : A
Explanation
Let original rate be R%. Then, new rate = (2R)% therefore 725 x R x 1⁄100 + 362.50 x 2R x 1⁄100 x 3 = 33.50 = (2175 + 725) R = 33.50 x 100 x 3 = 10050 = R = 10050⁄2900 = 3.46%
Q 9 - A sum of money becomes "n" times in "t" years at simple interest. Find the rate of interest per annum in terms of "n" and "t".
Answer : A
Explanation
Let Rs P become Rs nP in t years of time.
I = nP P = Rs P(n 1)
We know,
R = 100*I/PT
= 100*P(n 1)/Pt
= {100(n 1)/t}%