Volume Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The length, expansiveness and tallness of a cuboid are in the proportion 6:5:4 and its entire surface region is 33300 cm2. Its volume is:

A - 45000 cm3

B - 405000 cm3

C - 455000 cm3

D - information deficient

Answer : B

Explanation

Let length = 6x cm, breadth = 5x cm and height = 4x cm
Whole surface area = 2(lb+ bh + lh)
=2 (6x*5x + 5x *4x + 6x *4x) cm2 = (148x2) cm2
∴148x2= 33300 ⇒x2 = 225 ⇒x = √225 = 15 cm
∴L= 90 cm   , B= 75 cm and h= 60 cm
∴Volume = (L*b*h) = (90*75*60) =405000cm3

Q 2 - A rectangular water tank is open at the top. Its ability is 24m3. Its length and broadness are 4m and 3m separately. Overlooking the thickness of the material utilized for building the tank, the aggregate expense of painting the internal and external surfaces of the tank at Rs 10 for every m2, is:

A - Rs 400

B - Rs. 500

C - Rs. 600

D - Rs. 800

Answer : D

Explanation

Let the depth of the tank be x meters. Then, 4*3*x = 24 ⇒x =2m
Area of the surface to be painted = 2* [{2*(L+b)*h} + (L*b)}]
= 2*[2*(4+3)*2+ (4*3)] m2= 80m2
Cost of painting = (80*10) = 800 Rs.

Q 3 - The measurements of a cuboid are a, b,c units, its volume is V cubic units and its entire surface zone is S sq. units. At that point, 1/V=?

A - S/2(a+b+c)

B - 2/S(1/a + 1/b+ 1/c)

C - 2S(a+b+c)

D - 2S/(a+b+c)

Answer : B

Explanation

1/V =(1/S*S/V) = 2(ab+bc+ca)/s*abc=   2/S(1/a+1/b+1/c)

Q 4 - Water streams into a tank 200m *150m through a rectangular funnel 1.5m*1.25m at the rate of 20 kmph. In what the reality of the situation will become obvious eventually water rise By 2 meters?

A - 76 min

B - 80 min

C - 90 min

D - 96 min

Answer : D

Explanation

Volume of the water flown in the tank= (200*150*2) m3= 60000m3
Volume flown per hour = (3/2*125/100*20*1000) m3=37500m3
Time taken = 60000/37500 = 8/5 hrs = (8/5*60) min. = 96 min.

Q 5 - The aggregate surface zone of a solid shape is 150 cm2. Its volume is:

A - 64 cm3

B - 125 cm3

C - 150 cm3

D - 216 cm3

Answer : B

Explanation

6a2=150 ⇒a2= 25 ⇒a =5cm
Volume of the cube = a3= (5*5*5) cm3= 125cm3

Q 6 - The aggregate surface zone of 3D square (cube) is 1734 cm2 .Its volume is:

A - 2197 cm3

B - 2744 cm3

C - 4096 cm3

D - 4913 cm3

Answer : D

Explanation

6a2=1734 ⇒a2=289= (17) 2 ⇒a= 17
Volume = a3= (17*17*17) cm3= 4913cm3

Q 7 - A rectangular box measure s inside 1.6 m long, 1m expansive and 60 cm profound. The no. of cubical obstructs each of edge 20 cm that can be pressed inside the crate, is:

A - 30

B - 53

C - 60

D - 120

Answer : D

Explanation

Required no. = (160*100*60)/ (20*20*20) = 120

Q 8 - Water streams out through a round funnel whose inner measurement is 2cm, at the rate of 6 meters for each second into a barrel shaped tank, the range of whose base is 60 cm. By what amount will the level of water ascend in 30 minutes?

A - 2 m

B - 3 m

C - 4 m

D - 5 m

Answer : B

Explanation

Length flown in 30 minutes = (6*60*30) m =   10800 m
r = 1/100m, h = 10800 m
Volume = (π*1/100*1/100*10800) m3
Let the height of the water level be h meters. Then,
π*60/100*60/100*h = π*1/100*1/100*10800
⇒ h = (108/100*5/3*5/3) = 3m

Q 9 - The bended surface region and the aggregate surface zone of a barrel are in the proportion 1:2. In the event that the aggregate surface territory of the barrel is 616 cm2, then its volume:

A - 1078 cm3

B - 1232 cm3

C - 1848 cm3

D - none of these

Answer : A

Explanation

2πrh/2πr (h+r) =1/2⇒ h/(h+r)=1/2 ⇒2h= h+r⇒h=r
2πr (h+r) = 616 ⇒2πr*2r= 616 ⇒πr2= 154
⇒22/7*r2=154 ⇒   r2 = (154*7/22) =49
⇒   r = 7cm and h= 7cm
∴ Volume of cylinder = πr2h = (22/7*7*7*7) cm3= 1078 cm3

Q 10 - If the sweep of circle is 6cm, then its volume is:

A - (288π) cm3

B - (388π) cm3

C - (684π) cm3

D - (864π) cm3

Answer : A

Explanation

Volume = {4/3π*(6)3} cm3 = (4/3π*6*6*6) cm3= (288π) cm3

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