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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The entire surface range of a cuboid 24 cm long, 14 cm wide and 7.5 cm high is:
Answer : C
Explanation
Zone of the entire surface = 2(Lb+ bh +Lh) = 2 (24*14 + 14*15/2 + 24* 15/2) cm2 = 2(336+105+180) cm2= (621*2) cm2 = 1242 cm2
Q 2 - A rectangular tank is 225m by 162 m at the base. With what pace must water stream into it through an opening 60cm by 45 cm that the level may be brought 20cm up in 5 hours?
Answer : C
Explanation
Volume of water flown in 5hrs.= (225*162*20/100)= 7290 m3 Let the speed of the water be x meter /hr. Water flown in 5 hrs. =(x*60/100*45/100*5) m3= (27x/20) m3 ∴ 27x/20= 7290 ⇒ (7290*20/27) m = 5400m /hr.
Q 3 - A tank is 7m long and 4m wide. At what pace ought to water gone through a channel 5 cm expansive and 4cm profound so that in 6 hours and 18 minutes, water level in the tank ascends by 4.5m?
Answer : B
Explanation
Volume of water flown = (7*4*9/2) m3=126 m3 Let the speed of the water be x km/hr. (x*1000*63/10)*5/100*4/100= 126 ⇒ 63x/5=126 ⇒x = (5*126)/63= 10 ∴ Speed of water = 10 km/hr
Q 4 - A reservoir of limit 8000 liters measures remotely 3.3m by 2.6m by 1.1m and its dividers are 5cm thick. The thickness of the base is:
Answer : B
Explanation
Volume of the cistern = 8000ltr. =8000dm3 External length = 33 dm, external breadth =26 dm and external depth = 11 dm Internal length = (33-5/10*2) dm = 32 dm Internal breadth = (26-5/10*2) dm = 25 dm Internal depth = (11-x) dm ∴ 32*25*(11-x) = 8000 ⇒ (11-x) =8000/ (32*25) =10 ⇒ x = (11-10) =1dm
Q 5 - The diagonal of a 3D shape (cube) measures 9√3 cm. Its aggregate surface range is:
Answer : B
Explanation
√3a= 9√3 ⇒a= 9 cm Total surface area = 6a2= (6*9*9) cm2= 486cm2
Q 6 - The numerical estimations of volumes and entire surface region of a solid shape are equivalent. The region of every face of such 3D square (cube) has the numerical worth:
Answer : D
Explanation
a3=6a2 ⇒a=6 ⇒a2= 62= 36
Q 7 - Capacity of a round and hollow vessel is 25.872ltr. On the off chance that the stature of the chamber is three times the range of its base, what is the region of the base?
Answer : B
Explanation
Volume =(25.872*1000)cm3= 25872cm3 Let the radius be r cm. Then, height = 3r cm ∴22/7*r2*3r= 25872 ⇒r3= (25872*7)/66 = (392*7) = (7*7*7*8) ⇒r = (7*2) cm= 14 cm Area of the base = πr2= (22/7*14*14) cm2= 616 cm2
Q 8 - A divider with 10 m inside diameter is burrowed 14 m profound. Earth taken out of it is spread all around to a width of 5 m to shape a dike. The tallness of the bank is:
Answer : C
Explanation
Volume of the earth dugout = πr2h = (22/7* 5*5*14) m3= 1100m3 Area of embankment = π (R2- r2) = 22/7*[(10)2-(5)2] = (22/7*75) m2 Let the height of the embankment be h meters. Then, 22/7*75*h = 1100 ⇒h = (1100*7/22*1/75) m = 14/3 m = 4.66m
Q 9 - The bended surface zone of a round column is 528m2 and its volume is 2772 m3. The tallness of the column is:
Answer : C
Explanation
2πrh= 528 and πr2h= 2772 Πr2h/2πrh= 2772/528= 21/4⇒r = (21/4*2) = 21/2 m ∴2*22/7*21/2*h= 528 ⇒h =528/66= 8m
Q 10 - In the event that the sweep of a circle is multiplied, its surface region will increment by:
Answer : C
Explanation
Let, original radius=r. Then surface area= 4πr2 New radius= 2r. New surface area = 4π (2r) 2= 16πr2 Increase % in surface areas = (12πr2/4 πr2*100) %= 300%