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Progression - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The twelfth term of the A.P. 14, 9, 4, - 1, - 6....is:

Answer : D

Explanation

 Here a = 14, d = (9 - 14) = -5.
∴ T₁₂ = a + (12 -1) d = a + 11d = 14 + 11 * (-5) = -41.

Q 2 - What number of 3-digit numbers is distinguishable by 6?

Answer : B

Explanation

Requisite numbers are 102, 108, 114, 120,..., 996.
This is an A.P. in which a = 102 and d = (108-102) = 6
a + (n-1) d = 996    ⇒   102+ (n-1)*6 = 996   ⇒ (n-1)*6 =894    ⇒ (n-1) = 149    ⇒ n = 150

Q 3 - The main term of a number-crunching movement is 6 and its normal distinction is 5. The eleventh term is:

Answer : D

Explanation

Here a =6 and d = 5
T₁₁    = a + (11-1) d = a +10 d = (6+10*5) =56.

Q 4 - What is the following number in the math movement 2, 5, 8....?

Answer : D

Explanation

This is an A.P. in which a = 2 and d = (5-2) =3.
∴ Next number= (8+3) =11.

Q 5 - The total of initial 20 odd regular numbers is:

Answer : C

Explanation

Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.

Q 6 - Which term of the G.P. 5,10,20,40 ...is 1280?

Answer : B

Explanation

Let T_n = 1280. Then ar (ⁿ⁻ⁱ) = 1280 ⇒ Here a= 5 and r =2
∴ 5*2(ⁿ⁻ⁱ) =1280 ⇒256 = 2(ⁿ⁻ⁱ) =2⁸ ⇒ n-1 =8 ⇒ n= 9

Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?

Answer : C

Explanation

For any two unequal numbers a and b, we have (A.M).> (g.m)
∴   (a+b)/2 > √ab

Q 8 - A man heaps logs of wood so that the top layer contains one log and every lower layer has one more than the layer above. In the event that there are 15 layers, the aggregate number of logs will be:

Answer : B

Explanation

Total number of logs = 1+2+3+...+15.
This is an A.P. in which a =1, d =1 and n= 15.
Sn = n/2(a+1) = 15/2 (1+15) =120

Q 9 - In the event that (1² + 2² + 3²+ ......... + x²) = x(x+1) (2x+1)/6, then (1² + 3²+ 5² + ...... + 19²) =?

Answer : A

Explanation

(1²+ 3²+5²+..........+19²) = (1²+2²+3²+4²+5²+........+18²+19²) - (2²+4²+6²+.........+18²)
 = {19*(19+1) (38+1)/6} - (1*2²+2²*2²+2²*3²+2²*4²+???. +2²*9²)
= 2470 -2²*{1²+2²+3²+... +9²} = 2470 - (4*9*10*19)/6= (2470-1140) =   1330

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