Graphing a line in quadrant 1



We graph a line whose equation is given, say for example y = 3x. We need at least two points or ordered pairs to graph the line. First we choose some x values. Then we evaluate y = 3x for each value of x.

For example for x = 0, y = 3(0) = 0; x = 1, y = 3(1) = 3 and so on. We put the x, y and the ordered pair (x, y) values as follows.

x y (x,y)
0 3(0) = 0 (0,0)
1 3(1) = 3 (1,3)
2 3(2) = 6 (2,6)
3 3(3) = 9 (3,9)
4 3(4) = 12 (4,12)

We see that the ordered pairs lie in the quadrant 1. Joining the points will give the graph of the line in quadrant 1.

Graphing a line in quadrant 1

Graph the line in the quadrant 1, whose equation is given below.

2x – y = 3

Solution

Step 1:

Given equation 2x – y = 3; for y = 0, x = 3/2; for x = 2, y = 2(2)–3 = 4–3 = 1. So two ordered pairs are (3/2, 0) (2, 1)

Step 2:

Plotting the points and joining with a line we get

Graphing a line in quadrant 1 Example1 Step2

Graph the line in the quadrant 1, whose equation is given below.

x + 3y = 1

Solution

Step 1:

Given equation x + 3y = 1; for y = 0, x = 1; For x = 0, y = 1/3. So two ordered pairs are (1, 0) and (0, 1/3)

Step 2:

Plotting the points and joining with a line we get

Graphing a line in quadrant 1 Example2 Step2
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