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Volume Calculation - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The entire surface range of a cuboid 24 cm long, 14 cm wide and 7.5 cm high is:

Answer : C

Explanation

Zone of the entire surface = 2(Lb+ bh +Lh)
= 2 (24*14 + 14*15/2 + 24* 15/2) cm²
= 2(336+105+180) cm²= (621*2) cm²
= 1242 cm²

Q 2 - An open box is comprised of a metal. It is 50cm long, 40cm expansive and 23 m high. The thickness of the metal is 3cm. In the event that 1 cubic cm of the metal weighs 0.5 gm, then what is the heaviness of the void box?

Answer : D

Explanation

Volume of metal = [(50*40*23)-(44*34*20)]c m³
= 46000-29920=   16080 cm³
Weight of metal = (16080*5/10*1/1000) kg = 8.04 kg
Weight of the empty box = 8.04 kg

Q 3 - The whole of the length, broadness and profundity of a cuboid is 19 cm and its askew is 5√5cm. Its surface region is:

Answer : B

Explanation

(L+b+h) =19 and √ (L²+b²+h²) = 5√5
⇒ (L+b+h) ²= (19) ² and (L²+b²+h²) = 125
⇒ (L²+b²+h²) +2(Lb+bh+Lh) = 361 and (L²+b²+h²) = 125
⇒125+2(Lb+bh+Lh) =361 ⇒2 (Lb+bh+Lh) = (361-125) =236
∴ Surface area = 236cm²

Q 4 - The surface territory of a (10cm *4cm*3cm) block is:

Answer : C

Explanation

Here L =10 cm, b= 4 cm, h = 3cm
Surface area = 2(Lb+bh+Lh)
= 2(10*4+4*3+10*3) cm² = 2*82 = 164cm²

Q 5 - Six equivalent 3D shapes (cube), each of side 10 cm are set adjoining one another. The aggregate surface territory of the cuboid so framed, is:

Answer : B

Explanation

For the new cuboid, we have
L= (6*10) cm= 60cm, b= 10 cm and h= 10 cm
Total surface area = 2(Lb+bh+Lh)
= 2(60*10+10*10+60*10) cm²= 2600cm²

Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:

Answer : B

Explanation

2*volume of cube= volume of cuboid= (9*8*6) cm³
Volume of cube = (1/2 *9*8*6) cm³= 216cm³
∴ a³= 216 = (6) ³ ⇒a =6 cm
Total surface area = 6a² = (6*6*6) cm²= 216cm²

Q 7 - Capacity of a round and hollow vessel is 25.872ltr. On the off chance that the stature of the chamber is three times the range of its base, what is the region of the base?

Answer : B

Explanation

Volume =(25.872*1000)cm³= 25872cm³
Let the radius be r cm. Then, height = 3r cm
∴22/7*r²*3r= 25872 ⇒r³= (25872*7)/66 = (392*7) = (7*7*7*8)
⇒r = (7*2) cm= 14 cm
Area of the base = πr²= (22/7*14*14) cm²= 616 cm²

Q 8 - A round and hollow has a width of 14cm and the territory of its bended surface is 220 sq. cm. The volume of the chamber is:

Answer : A

Explanation

r = 7cm and 2 πrh  = 220 ⇒2*22/7*7*h = 220 ⇒h = 5 cm
Volume = πr²h (22/7*7*7*5) = 770 cm³

Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:

Answer : B

Explanation

2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm
Outer radius = 70cm, inner radius = (70-4) = 66cm
Volume of iron = π [(70)²-(66)²*63cm³= (22/7*136*4*63)
= 58752 cm³

Q 10 - If the radii of the two circles are in the proportion 1:4, then their surface regions will be in the proportion?

Answer : B

Explanation

Let their radii be rand 4r.
Ratio of their surface areas= 4πr²/4π (4r) ²= r²/16 r²= 1/16= 1:16

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