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Aptitude - Calendar Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Calendar. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
4Th.june, 2002 = (2001 years+ period from 1.1.2002 to. 4.6.2002. Odd days in 1600 years = 0 Odd days in 400 years = 0 Odd days in 1 customary years = 1 Odd days in 2001 years = (0+0+1)=1 Jan + Feb. +March +April+ May +June (31 + 28 +31+ 30 + 31 +4 = 155 days=22 weeks +1 day = 1 odd days Aggregate no. of odd days = (1+1) = 2 ∴ required day is Tuesday.
Q 2 - Jan.1, 2007 was Monday. What day of the week lies on Jan 1, 2008?
Answer : B
Explanation
The year 2007 is a common year. So, it has 1 odd day. First day of the year 2007 was Monday. First day of the year 2008 will be 1 day past Monday. Subsequently, it will be Tuesday.
Q 3 - Jan.1 2008 is Tuesday. What date of the week lies on Jan 1, 2009?
Answer : C
Explanation
The year 2008 is a jump year. So, it has 2 odd days. First day of the year 2008 is Tuesday (Given). In this way, first day of the year 2009 is 2 days past Tuesday. Subsequently, it will be Thursday.
Q 4 - On sixth March, 2005 Monday falls. What was the day of the week on sixth March, 2004?
Answer : B
Explanation
The year 2004 is a jump year. In this way, it has 2 odd days. ∴ The day on sixth March, 2005 will be 2 days. past the day on sixth Walk, 2004. Yet, sixth March, 2005 is Monday. ∴ sixth March, 2004 is Saturday.
Q 5 - on what dates of April, 2001 did Wednesday fall?
Answer : D
Explanation
We might discover the day on first April, 2001. First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001) Odd days in 1600 years =0. Odd days in 400 year =0. Jan Feb March April 31 + 28 + 31 + 1 = 91 days =0 odd day. Aggregate number of odd days= (0+0+0) =0. On first April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Answer : D
Explanation
28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006) Odd days in 1600 years=0. Odd days in 400 years = 0. 5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days = 6 odd days. Jan + Feb. + March + April + May 31 + 28 + 31 + 30 + 28 =148 days. 148 days = (21 weeks+1 day) = 1 odd day Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day. Given day is Sunday.
Answer : C
Explanation
100 years contain 5 odd days. ∴ Last day of first century is Friday. 200 years contain (5*2) = 3 odd days. ∴ Last day of second century is Wednesday. 300 year contain (5*3) =15=1 odd day. ∴ Last day of third century is Monday. 400 year contain 0 odd days. ∴ Last day of fourth century is Sunday. The cycle is repeated. ∴ Last day of a century can't be Tuesday or Thursday or Saturday.
Answer : A
Explanation
The century divisible by 400 is a leap year. ∴ The year 700 is not a jump year.
Q 9 - On eighth Feb, 2005 it was Tuesday. What was the week's day on eighth Feb, 2004?
Answer : C
Explanation
The year 2004 is a jump year. It has 2 odd days. ∴ The day on eighth Feb,2004 is 2 days before the day. On eighth Feb, 2005. Henceforth This day is Sunday.
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