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Aptitude - Arithmetic Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - What is y if 2y, y+10, 3y+2 are in an A.P.?

Answer : C

Explanation

    
As numbers are in A.P.  
Thus (y + 10) - 2y = (3y + 2) - (y + 10)  
=> 10 - y = 2y - 8  
=> -3y = -18  
=> y = 6

Q 2 - Find the number which being increased by 1 will be exactly divisible by 13, 15 and 19?

Answer : A

Explanation

  
LCM of 13, 15 and 19 is 3705  
So the desired number is3705-1=3704

Q 3 - The difference between local and the face value of 8 in the numeral is 568012?

Answer : C

Explanation

  
 8000 - 8 
 = 7992

Q 4 - The product of two successive positive integers is 462. Which is the smaller integer?

Answer : C

Explanation

  
 Suppose the two consecutive integers be y and y + 1 respectively.  According to question,       
 (y) x (y + 1) = 462  
 Or, y² + y - 462 = 0  
 Or, y² + 22y - 21y - 462 = 0  
 Or, y(y + 22) - 21(y + 22) = 0  
 Or, (y + 22) (y - 21) = 0  
 Or, y = 21

Q 5 - How many multiples of 3 are available between 15 and 105 including both?

Answer : B

Explanation

 
 Here numbers are 15, 18, ..., 105 which is an A.P. 
 Here a = 15,  d = 3,    
 Using formula T_n = a + (n - 1)d    
 T₁₁ = 15 + (n - 1) x 3 = 105 
 => 12 + 3n = 105 
 => n = 93 / 3 = 31

Q 6 - What is the sum of all odd numbers between 100 and 200?

Answer : D

Explanation

  
 Required sum = 101 + 103 + ... + 199 which is an A.P. where a = 101, d = 2, l = 199.  
 Using formula T_n = a + (n - 1)d  
 T_n = 101 + (n-1)2 = 199  
 => 2n = 199 - 99 = 100  
 => n = 50  
 Now Using formula S_n = (n/2)(a + l)  
 ∴ Required sum = (50/2)(101+199)  = 50 x 150  = 7500

Q 7 - If 4^th and 9^th terms of a G.P. are 54 and 13122 then what will be the 2^nd term?

Answer : A

Explanation

   
 Using formula T_n = ar^{n- 1}  
 T₄ = ar^{(4 - 1)}  
 => ar³ = 54 ... (i)  
 T₉ = ar^{(9 - 1)}  
 => ar⁸ = 13122 ... (ii)  
 Dividing (ii) from (i)  
 => r⁵ = 243 = 3⁵ 
 => r = 3  
 Using (i)  a = 54 / 9 = 6

Q 8 - (1³ + 2³ ... + 15³) = ?

Answer : D

Explanation

  
 Using formula  (1³ + 2³ ... +  n³) = [(1/2)n(n+1]²  
 (1³ + 2³ ... + 15³) 
 = [(15 x 16)/2]²  
 = 120²  = 14400

Q 9 - What is the 115^th term of A.P. 4, 4.5, 5, 5.5 ... ?

Answer : C

Explanation

 Here a = 4, d = 4.5 - 4 = 0.5, n = 115 
 Using formula T_n = a + (n - 1)d 
 T₁₁₅ = 4 + (115 - 1) x 0.5 
 = 59

Q 10 - If n^th term of the series 72, 63, 54, ... is 9. What is n?

Answer : A

Explanation

   
 Here a = 72,  d = 63 - 72 = -9,    
 Using formula T_n = a + (n - 1)d    
 T_n = 72 + (n - 1) x -9 = 9    
 => 81 - 9n = 9   
 => n = 8

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