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Aptitude - Ratios Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Divide Rs. 1500 among U,V,W,X so that u and V together get thrice as much as W and X together, V gets four times of what W gets and W gets 1.5 times as much as X. V gets Rs
Answer : B
Explanation
U+V+W+X=1500 ------ (1) Here U+V=3(W+X) From (1) And 4(W+X) =1500 => W+X=375 U+V=1125 Given that V=4W & W=1.5X => 2.5X = 375 => X=150 => V=4*1.5*X=900
Q 2 - If 420 Mangoes was distributed among three children's in the ratio 1/3:2/3:3/4 , how many bananas did the first child get?
Answer : B
Explanation
1/3:2/3:3/4=(4:8:9)/12 Mangoes are in the ratio 4x:8x:9x 4x+8x+9x = 420 => x=20 => First child get 4*20=80 mangoes
Q 3 - If A:B =1/2:3/8 , B:C =1/3:5/9 and C:D =5/6:3/4 then , A:B:C:D=?
Answer : C
Explanation
A:B = 1/2 : 3/8 =4 :3 , B:C = 1/3 :5/9 = 3:5 and C:D = 5/6 : 3/4 = 10 :9 A:B = 4:3 , B:C = 3 :5 , C:D = 10/2 :9/2 = 5 :9/2 A:B:C:D = 4:3:5:9/2 = 8 :6: 10 :9
Answer : C
Explanation
Now x/y =3/4 (7x+3y)/(7x-3y) = (7 * x/y + 3)/(7 * x/y -3) = (7 *3/4 +3)/(7* 3/4 - 3 ) = (21+12)/(21-12) = 33/9 =11/3 ∴ (7x+3y) : (7x-3y)= 11:3
Q 5 - Which of the following function can be used to get an array in the reverse order?
Answer : A
Explanation
array_reverse(): Returns an array in the reverse order.
Q 6 - What must be added to each term of the extent 7:13 so that the extent gets the chance to be 2:3 ?
Answer : D
Explanation
Let the number to be added be X. Then, 7+x/13+x= 2/3 => 3(7+X)=2(13+x) => X= (26-21)= 5 ∴ number to be added = 5.
Q 7 - The proportion of two numbers is 3:4 and their entirety is 420.The more noteworthy of the Two numbers is:
Answer : C
Explanation
Let the numbers be 3x and 4x , Then 3x+4x= 420 => 7x= 420 => x=60. So, the numbers are 180 and 240. Hence, the correct answer is 240 .
Q 8 - if the wage of A is 10% more than that of B and the wage of B is 20 % not as much as that of C, than the pay of A,B, C are in the proportion.
Answer : B
Explanation
Let C income be Rs 100. Then, B income=Rs 80. A income=(110% of Rs 80)=Rs(110/100*80)=Rs 88. ∴A:B:C=88:80:100=22:20:25.
Q 9 - Rs. 600 are partitioned among A, B and C such that Rs. 40 more than 2/fifth of An offer , Rs. 20 more than 2/7 of B offer and Rs. 10 all the more then 9/17 of C offer may all be equivalent . What is A's offer?
Answer : B
Explanation
(2/5)A +40 = ( 2/7)B +20 + 9/17 C+10 = k. Then, A =5/2 (k-40), B= 7/2(k-20) and C= 17/9 (k-10) A+B+C =600 =>5/2 (k-40) +7/2(k-20) + 17/9 (k-10) = 600 => 45(k-40) +63(k-20)+34(k-10)= 10800 => 142k- (45*40+63*20+34*10) =10800 => 142k- (10800+3400) = 14200 =>k=100. ∴ A= 5/2(100-40)= (5/2*60) =150
Q 10 - Rs 1300 are separated among A,B,C and D in a manner that: A share / B share = B share / C share =C share/ D share = 2/3, What is A share?
Answer : C
Explanation
A:B=2:3,B:C=2:3=3/2*2:3/2*3:9/2. C:D=2:3=2*9/4:3*9/4=9/2:27/4. ∴ A:B:C:D=2:3:9/2:27/4=8:12:18:27. A share =Rs(1300*8/65)=Rs160.
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