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Aptitude - Pipes & Cisterns Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Pipes & Cisterns. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - In 1 minute 3/7 of a basin is filled. Whatever remains of the container can be filled in:

Answer : B

Explanation

Part filled in 1 min. = 3/7. remaining part = (1- 3/7)= 4/7
Let the required time be x min.
More part, more time taken. (Direct)
3/7: 4/7:: 1: x ⇒ 3x/7 = (4/7*1) ⇒ x= 4/3 min.

Q 2 - A pump can fill a tank with water in 2 hours. In light of a break in the tank, it takes 7/3 hours to fill the tank. The hole can discharge the filled tank in:

Answer : D

Explanation

Part filled by the pump in 1 hr = 1/2
Net part filled by the pump and leak in 1 hr = 3/7
Emptying work done by the leak in 1 hr= (1/2 - 3/7)= 1/14
Leak can empty the tank in 14 hours.

Q 3 - Pipes A and B can fill a tank in 20 hours and 30 hours separately and channel C can purge the full tank in 40 hours. In the event that every one of the funnels is opened together, what amount of the reality of the situation will become obvious eventually expected to make the tank full?

Answer : C

Explanation

Net part filled in 1 hr = (1/20+ 1/30 ? 1/40)= 7/120
Time needed to make the tank full = 120/7 hrs.

Q 4 - Two pipes A and B can fill a tank in 15 minutes and 20 minutes separately. Both the channels are opened together. Be that as it may, following 4 minutes, pipe is turned off. What is the aggregate time required to fill the tank?

Answer : D

Explanation

Part filled by both in 4 min. = 4*(1/15+1/20)= (4*7/60)= 7/15
Part unfilled = (1-7/15) = 8/15
1/20 part is filled by B in 1 min.
8/15 part is filled by B in (20*8/15) min. = 32/3 min = 10 min 40 sec.
Total time taken = (4 min+10 min 40 sec.) = 14 min 40 sec.

Q 5 - A tank is fitted with two taps A and B. A can fill the tank totally in 45 minutes and B can purge the full tank in 60 minutes. On the off chance that both the taps are opened on the other hand for 1 minute, then in what amount of time the unfilled tank will be filled totally?

Answer : D

Explanation

Work done by A in 1st minutes and B 2nd minute= (1/45- 1/60)= 1/180
Part filled in 2 min = 1/180
Part filled in 358 min = (1/360*358) =   358/360 = 179/180
Remaining part = (1-179/180) = 1/180
1/45 part is filled by A in (45*1/180) min= 1/4 min.
Total time taken to fill it = 358 1/4 min = 5 hrs.58 min 15 sec.

Q 6 - Three funnels A, B; C can fill a tank in 6 hours. In the wake of working at it together for 2 hours, C is shut and A and B can fill the remaining part in 7 hours. The quantity of hours taken by C alone to fill the tank is:

Answer : C

Explanation

Part filled by (A+B+c) in 2 hours= (1/6*2)=1/3
2/3 part is filled by (A+B) in 7 hours.
Whole is filled by (A+B) in (7*3/2) hr=21/2hrs.
Part filled by C in 1 hour = (1/6-2/21) = 3/42 = 1/14
∴C alone can fill it in 14 hours.

Q 7 - If two funnels work at the same time, the repository will be filled in 12 hours. One channel fills the store 10 hours quicker than the request. How long does the speedier funnel take to fill the store?

Answer : C

Explanation

Suppose that one pipe takes x hours to fill the reservoir.
Than the other pipes takes (x-10) hours.
∴ 1/x+ 1/(x-10) = 1/12 ⇒12(x-10+x)= x(x-10)
⇒x²-34x +120=0 ⇒(x-30) (X-4) =0
⇒x= 30 or x= 4
So, the faster pipe takes 30 hrs to fill the reservoir.

Q 8 - Two pipes A and B can ill a tank in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

Answer : D

Explanation

T = xy/(x+y)
= (36*45)/(36+45)
= 1620/80
= 20 hours

Or,

Part filled by A in 1 hour = 1/36
Part filled by B in 1 hour = 1/45
Part filled by (A+B) in 1 hour = (1/36 + 1/45) = 1/20

∴ Both the pipes can fill the tank in 20 hours.

Q 9 - A pump can fill a tank with water in 2 hours. Because of a leak in the tank, it takes 7/3 hours to fill the tank. The leak can empty the filled tank in?

Answer : D

Explanation

Part of the tank filled by the pump in 1 hour = 1/2
Part of the tank filled by the pump in 1 hour because of the leak = 3/7
∴ Part of the tank emptied by the leak in 1 hour = 1/2 - 3/7
= 1/14
∴ Leak will empty the tank in 14 hours.

Q 10 - A cistern can be filled by two pipes in 20 and 30 min respectively. Both pipes being open, when must the first pipe be turned off so that so that the cistern may be filled in 10 min more?

Answer : D

Explanation

In 1 min both pipes can fill = 1/20 + 1/30
= 1/12
In 10 min second pipe can fill = (1/30)*10 = 1/3 part
Part of cistern filled by both the pipes = 1 - 1/3
= 2/3
1/12 part is filled in 1 min
∴ 2/3 part will be filled in 12*2/3 = 8 min
Hence, first first pipe should be turned off after 8 min.

aptitude_pipes_cisterns.htm