Trains - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Trains. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A train with a speed of 60 kmph crosses a pole in 30 seconds. The length of the train is

A - 500 m

B - 750 m

C - 900 m

D - 1000 m

Answer : A

Explanation

speed =  (60*5/18)m/sec  = 50/3 m/sec.
Length of the train = (50/3* 30)m = 500 m 

Q 2 - A train travelling at a speed of 30 m/sec crosses a platform 600 m long in 30 sec. The length of the train is?

A - 120 m

B - 150 m

C - 200 m

D - 300 m

Answer : D

Explanation

Let the length of the train be X m . then its speed =(600+x)/30 m/sec.
∴ (600+X)/30 =30 ⇒ 600+x =900 ⇒ x =300m

Q 3 - A train 270 m long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2kmph in

A - 36 sec

B - 32 sec

C - 28 sec

D - 24 sec

Answer : A

Explanation

Their relative speed =(25+2)kmph =27kmph  = (27*5/18) m/sec. =15/2 m/sec.
Required time = 270/ (15/2) sec. = (270*2)/15   sec.= 36 sec.

Q 4 - A train overtakes two persons two persons walking in the same direction in which the train is going. These persons are walking at the rate of 2km/hr and 4km/hr and the train passes them completely in 9 sec. and 10 sec. respectively. The length of the train is

A - 72 m

B - 54 m

C - 50 m

D - 45 m

Answer : C

Explanation

let the length of the train be X km and its speed be y km/hr.
Speed of the train relative to first man = (y-2) km/hr
Speed of the train relative to second man =(y-4)km/hr
∴ x/(y-2) = 9/(60*60) and x/(y-4) =10/(60*60)
⇒ y-2 =400x and y-4 =360x
⇒ 400x+2=360x+4 ⇒40x=2 ⇒x=1/20km =(1/20*1000)m= 50m
∴ length of the train =50m

Q 5 - A train takes 5 sec. to pass an electric pole. If the length of the train is 120 m, the time taken by it to cross a railway platform 180 m long ,is

A - 25/2 sec

B - 15/2 sec

C - 13/2 sec

D - 10/3 sec

Answer : A

Explanation

Speed of the train = (120/5)m/sec. =24m/sec.
Time taken to cross the platform =(120+180)/24 sec. =300/24 sec= 25/2 sec.

Q 6 - A train is running at 36kmph completely crosses another train having half its length and travelling in the opposite direction at 54kmph, in 12 seconds. If it passes a platform in 3/2 minute , the length of the platform is

A - 560 m

B - 600 m

C - 700 m

D - 750 m

Answer : C

Explanation

Let the length of slower train be x meters.
Then, the length of faster train = x/2 m.
Relative speed = (36+54)kmph =(90*5/18)m/sec. =25m/sec.
(x+x/2)/25= 12 ⇒  3x/2*25= 12  ⇒3x =600 ⇒ x =200
Length of slower train = 200m 
Let the length of the platform be y meters. Then,
(200+y)/(36*5/18)= 90 ⇒ 200+y= 900 ⇒ y= 700
Hence, the length of the platform is 700 m.

Q 7 - A train X start from Meerut at 4 pm and reaches Ghaziabad at 5p.m while another train Y start from Ghaziabad at 4p.m and reaches Meerut at 5.30 p.m . The two train will cross each other at

A - 4.36 pm

B - 4.42 pm

C - 4.48 pm

D - 4.50 pm

Answer : A

Explanation

Let the distance between meerut and Ghaziabad be x km.
Time taken by y to cover x km =3/2 hours.
Time taken by X to cover x km = 1 hours
Speed of x = xkm/hr    speed of y = 2x/3 km/hr 
Xy+2xy/3 =x   ⇒ y (1+2/3) =1 ⇒ y = 3/5 hours = (3/5*60) min. =36 min.
Hence, the two train meet at 4.36 p.m

aptitude_trains.htm
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