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Speed & Distance - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - A train is moving with a pace of 180 km/hr. Its rate is:

Answer : D

Explanation

180 km/hr = (180*5/18) m/sec = 50 m/sec.

Q 2 - The velocities of A and B are in the proportion 3:4. A takes 20 min. more than B to achieve a destination. In what time does A achieve the destination?

Answer : A

Explanation

Let the time taken by A be x hrs.
Then, time taken by B = (x-20/60) hrs = (x-1/3) hrs
Ratio of speeds = inverse ratio of time taken
∴3:4 =(x- 1/3): x ⇒3x-1/3x = 3/4
⇒12x- 4 = 9x
⇒3x= 4 ⇒x= 4/3 hrs
Required time = 4/3 hrs.

Q 3 - A auto going with 5/7 of its typical rate covers 42 km in 1 hr. 40 min. 48sec.What is the typical pace of the auto?

Answer : D

Explanation

Let the usual speed be x km/hr.
42/(5x/7)= 126/75 ⇒  42*7/5x = 42/25 ⇒5x = (25*7) ⇒x = (5*7) = 35

Q 4 - Bombay express left Delhi for Bombay at 14.30 hours, going at a rate of 60 kmph and Rajdhani express left Delhi for Bombay around the same time at 16.30 hours, going at a pace of 80 kmph. How far from Delhi will the two trains meet?

Answer : C

Explanation

Let the train meet at a distance of x km from Delhi. Then,
x/60 - x/80 = 2 ⇒ 4x-3x = 480 ⇒x = 480
∴ required distance = 480 km

Q 5 - A strolls at a uniform rate of 4 km an hours and 4 hours after his begin, B cycles after him at the uniform rate of 10 km an hours. How a long way from the Beginning stage will B get A?

Answer : D

Explanation

Suppose B catches A after x hours. Then,
Distance travelled by A in (x+4) hr. =distance travelled by B in x hours
4(x+4) =10x⇒6x=16⇒3x=8⇒x=8/3hrs.
Distance travelled by B in 8/3 hrs= (8/3*10)km=80/3km=26.7km.

Q 6 - A man strolling at 3 km/hr crosses a square field corner to corner in 2 minutes. The zone of the field is:

Answer : C

Explanation

Speed =(3*5/18)m/sec. = 5/6 m/sec
Distance covered in 2 min. = (5/6* 2* 60) m = 100 m
Length of the diagonal of the square field = 100 m
Area = 1/2 * (diagonal) ²= (1/2 *100 *100 )m²= 5000 m²
= 5000/100 ares = 50 ares {1 are= 100 m²}

Q 7 - A bullock truck needs to cover a separation of 80 km in 10 hours. On the off chance that it covers half of the excursion in 3/5 th of the time, what ought to be its velocity to cover the remaining separation in the time left?

Answer : C

Explanation

Distance left = (1/2 *80) km = 40 km
Time left = {(1-3/5)*10} hrs = (2/5*10)= 4hrs.
Speed required = 40/4 km/hr = 10 km/hr

Q 8 - The proportion between the rates of strolling of A and B is 2:3. In the event that the time taken by B to cover a sure separation is 36 minutes, the time taken by A to cover that much separation is

Answer : B

Explanation

Ratio of time taken = 1/2:1/3 = 3:2
Time taken by B = 36 min. let the time taken by A be x min.
∴x/36 = 3/2 ⇒x = (3*36/2) min. = 54 min

Q 9 - A auto finishes a sure excursion in 8 hours. It covers a large portion of the separation at 40 km/hr and the rest at 60 km/hr. The length of the adventure is:

Answer : C

Explanation

Let the total journey be x km. then,
(x/2 * 1/40)+ (x/2* 1/60) = 8 ⇒ x/80 + x/120 = 8
⇒3x+ 2x = 1920 ⇒5x= 1920 ⇒ x= 384
∴ Total journey = 384 km

Q 10 - A agriculturist voyaged a separation of 61 km in 9 hours. He voyaged halfway by walking at 4 km/hr and incompletely on bike at 9 km/hr. The separation went by walking is:

Answer : C

Explanation

Let the distance travelled on foot be x km
Then, distance covered on bicycle = (61-x) km
∴x/4 + 61-x/9 =9 ⇒ 9x+4(61-x)= 324 ⇒ 5x = (324-244)=  80 ⇒x = 16
Distance covered on foot = 16 km

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