- Perimeter and Area of Polygons
- Home
- Sides of polygons having the same perimeter
- Finding the missing length in a figure
- Perimeter of a piecewise rectangular figure
- Area of a rectangle involving fractions
- Distinguishing between the area and perimeter of a rectangle
- Areas of rectangles with the same perimeter
- Word problem involving the area of a square or a rectangle
- Finding the side length of a rectangle given its perimeter or area
- Area of a piecewise rectangular figure
- Area between two rectangles
- Finding the area of a right triangle on a grid
- Finding the area of a right triangle or its corresponding rectangle
- Area of a triangle
- Finding the area of a trapezoid on a grid by using triangles and rectangles
- Area involving rectangles and triangles
- Area of a parallelogram
- Area of a trapezoid
- Finding the perimeter or area of a rectangle in the coordinate plane

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# Area between two rectangles

In this lesson, we solve problems involving areas between two rectangles.

A rectangle is given and inside it a smaller rectangle is drawn and then the area between these rectangles is found as follows. Consider the following figure. There is a rectangle L × W. Inside it there is another rectangle l × w. The area between these rectangles is shaded. We find the area of this shaded region.

**Formula for finding area between rectangles**

Area between rectangles

= Area of bigger rectangle – Area of smaller rectangle

= L × W – l × w

Where the length and width of bigger rectangle are L and W and

Length and width of the smaller rectangle are l and w.

Find the area between the following pair of rectangles.

### Solution

**Step 1:**

Area of a rectangle = l × w; l = length; w = width

**Step 2:**

Area between the given pair of rectangles = 25 × 10 − 18 × 8

= 250 – 144

= 106 square m

Find the area between the following pair of rectangles.

### Solution

**Step 1:**

Area of a rectangle = l × w; l = length; w = width

**Step 2:**

Area between the given pair of rectangles = 27 × 20 − 16 × 5

= 540 – 80

= 460 square m