Write five pairs of integers $(a,\ b)$ such that $a ÷ b=-3$. One such pair is $(6,\ -2)$ because $6 ÷ (-2) = (-3)$.

Given:

$(a\div b) = -3$

To do:

We have to find out five pairs of integers (a,b) such that $(a \div b) = -3$.

Solution:

$(a \div b) = -3$

This implies, $a=-3(b)$

If 

$b=1, then\ a=-3(1)=-3$

$b=2, then\ a=-3(2)=-6$

$b=3, then\ a=-3(3)=-9$

$b=4, then\ a=-3(4)=-12$

$b=5, then\ a=-3(5)=-15$

Therefore, five pairs of integers other than $(6,-2)$ such that $a \div b = -3$ are $(-3,1), (-6,2), (-9,3), (-12,4)$ and $(-15,5)$.

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Updated on: 10-Oct-2022

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