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Working with MongoDB $sort for sub array document
For sub array document in MongoDB, use aggregate along with $sort. Let us first create a collection with documents −
> db.demo23.insertOne(
...{
...
... "StudentDetails" : [{
... "Name" : "David",
... "Age" : 23,
...
... }, {
... "Name" : "Adam",
... "Age" : 24,
... }]
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e14c3eb22d07d3b95082e71")
}Display all documents from a collection with the help of find() method −
> db.demo23.find().pretty()
This will produce the following output −
{
"_id" : ObjectId("5e14c3eb22d07d3b95082e71"),
"StudentDetails" : [
{
"Name" : "David",
"Age" : 23
},
{
"Name" : "Adam",
"Age" : 24
}
]
}Here is the query to work with $sort for sub array document −
> db.demo23.aggregate([
... { "$unwind" : "$StudentDetails"} ,
... { "$sort" : { "StudentDetails.Name" : 1}},
... { "$match" : { }} ,
... { "$group" : { "StudentDetails" : { "$push" : { "Name" : "$StudentDetails.Name"}} , "_id" : null}} ,
... { "$project" : { "_id" : 0 , "StudentDetails" : 1}}
... ]);This will produce the following output −
{ "StudentDetails" : [ { "Name" : "Adam" }, { "Name" : "David" } ] }
Updated on: 02-Apr-2020
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