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Why C treats array parameters as pointers?
C treats array parameter as pointers because it is less time consuming and more efficient. Though if we can pass the address of each element of the array to a function as argument but it will be more time consuming. So it’s better to pass the base address of first element to the function like:
void fun(int a[]) { … } void fun(int *a) { //more efficient. ….. }
Here is a sample code in C:
#include void display1(int a[]) //printing the array content { int i; printf("
Current content of the array is:
"); for(i = 0; i < 5; i++) printf(" %d",a[i]); } void display2(int *a) //printing the array content { int i; printf("
Current content of the array is:
"); for(i = 0; i < 5; i++) printf(" %d",*(a+i)); } int main() { int a[5] = {4, 2, 7, 9, 6}; //initialization of array elements display1(a); display2(a); return 0; }
Output
Current content of the array is: 4 2 7 9 6 Current content of the array is: 4 2 7 9 6
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