While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made the following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after three experiments = 35 g

The percentage of water absorbed by raisins is:

$(A) \frac{40 g -35 g}{35 g} ×100$

$(B) \frac{40 g- 35 g}{40 g} ×100$

$(C) \frac{8 g-5 g}{8 g} ×100$

$(D) \frac{8g - 5g}{5 g} ×100$

$(D) \frac{8g - 5g}{5 g} ×100$

Explanation

The percentage of water absorbed by raisins is calculated by using the formula:

$\frac{{W}_{2}-{W}_{1}}{{W}_{1}}\times 100$

where W₂ = the weight of wet resin and W₁ = the weight of the dry resin.

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Updated on: 10-Oct-2022

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