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Verify $a-(-b)=a+b$ for the following values of $a$ and $b$.
(i) $a=21, b=18$
(ii) $a=118, b=125$
(iii) $a=75, b=84$
(iv) $a=28, b=11$
Given:
Some values of $a$ and $b$.
To do:
We have to verify whether $a\ -\ ( -b) \ =\ a\ +\ b$
Solution:
We know that,
$(-) \times (-) = (+)$
Therefore,
(i) $a = 21, b = 18$
This implies,
$a\ -\ (-b)\ =21\ -\ (-18)$
$=\ 21\ +\ 18$
$=\ 39$
$a+b=21+18$
$=39$
Hence, $a\ -\ ( -b) \ =\ a\ +\ b$.
(ii) $a = 118, b = 125$
This implies,
$a\ -\ (-b)\ =118- (-125)$
$=\ 118\ +\ 125$
$= 243$
$a+b=118+125$
$=243$
Hence, $a\ -\ ( -b) \ =\ a\ +\ b$.
(iii) $a = 75, b = 84$
This implies,
$a - (-b) =75 - (-84)$
$=\ 75\ +\ 84$
$=\ 159$
$a+b=75+84$
$=159$
Hence, $a\ -\ ( -b) \ =\ a\ +\ b$.
(iv) $a = 28, b = 11$
This implies,
$a - (-b) =28 - (-11)$
$=\ 28\ +\ 11$
$=\ 39$
$a+b=28+11$
$=39$
Hence, $a\ -\ ( -b) \ =\ a\ +\ b$.
Hence, we can see that in every case $a\ -\ (-b)\ =\ a\ +\ b$.
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