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Uniform Initialization in C++
Here we will discuss about the uniform initialization in C++. This is supported from C++11 version. The uniform initialization is a feature that permits the usage of a consistent syntax to initialize variables and objects which are ranging from primitive type to aggregates. In other words, it introduces brace-initialization that applies braces ({}) to enclose initializer values.
Syntax
type var_name{argument_1, argument_2, .... argument_n}Initialize Dynamically allocated arrays
Example (C++)
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int main() {
int* pointer = new int[5]{ 10, 20, 30, 40, 50 };
cout<lt;"The contents of array are: ";
for (int i = 0; i < 5; i++)
cout << pointer[i] << " " ;
}Output
The contents of array are: 10 20 30 40 50
Initialization of an array data member of a class
Example
#include <iostream>
using namespace std;
class MyClass {
int arr[3];
public:
MyClass(int p, int q, int r) : arr{ p, q, r } {};
void display(){
cout <<"The contents are: ";
for (int c = 0; c < 3; c++)
cout << *(arr + c) << ", ";
}
};
int main() {
MyClass ob(40, 50, 60);
ob.display();
}Output
The contents are: 40, 50, 60,
Implicitly initialize objects to return
Example
#include <iostream>
using namespace std;
class MyClass {
int p, q;
public:
MyClass(int i, int j) : p(i), q(j) {
}
void display() {
cout << "(" <<p <<", "<< q << ")";
}
};
MyClass func(int p, int q) {
return { p, q };
}
int main() {
MyClass ob = func(40, 50);
ob.display();
}Output
(40, 50)
Implicitly initialize function parameter
Example
#include <iostream>
using namespace std;
class MyClass {
int p, q;
public:
MyClass(int i, int j) : p(i), q(j) {
}
void display() {
cout << "(" <<p <<", "<< q << ")";
}
};
void func(MyClass p) {
p.display();
}
int main() {
func({ 40, 50 });
}Output
(40, 50)
Updated on: 27-Aug-2020
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