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TypedArray.find() function in JavaScript
The find() function of TypedArray accepts a string value representing the name of a function, tests whether the elements in the array passes the test implemented by the provided function, if so, returns the first element which passes the test else, returns undefined.
Syntax
Its Syntax is as follows
typedArray.find(function_name)
Example
<html>
<head>
<title>JavaScript Array every Method</title>
</head>
<body>
<script type="text/javascript">
var int32View = new Int32Array([21, 19, 65,21, 14, 66, 87, 55 ]);
document.write("Contents of the typed array: "+int32View);
document.write("<br>");
function testResult(element, index, array) {
var ele = element>35
return ele;
}
result = int32View.find(testResult);
document.write("Result: "+result);
</script>
</body>
</html>Output
Contents of the typed array: 64,89,65,21,14,66,87,55 Result: 65
Example
If the Array doesn’t contain the required element this function returns undefined.
<html>
<head>
<title>JavaScript Array every Method</title>
</head>
<body>
<script type="text/javascript">
var int32View = new Int32Array([21, 19, 65,21, 14, 66, 87, 55 ]);
document.write("Contents of the typed array: "+int32View);
document.write("<br>");
function testResult(element, index, array) {
var ele = element>100
return ele;
}
result = int32View.find(testResult);
document.write("Result: "+result);
</script>
</body>
</html>Output
Contents of the typed array: 21,19,65,21,14,66,87,55 Result: undefined
Updated on: 25-Jun-2020
19 Views
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