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Two numbers are respectively 12 whole 1 upon 2% and 25% more than a third number. Find what percent is the first number of the second number?
Given:
Two numbers are respectively $12\frac{1}{2}\%$ and $25\%$ more than a third number.
To do:
We have to find what percent is the first number of the second number.
Solution:
Let the third number be 100.
This implies,
The first number$=100+\frac{12\frac{1}{2}}{100}\times100=100+12.5$
$=112.5$
The second number$=100+\frac{25}{100}\times100$
$=100+25=125$
First number as a percentage of the second$=\frac{112.5}{125}\times100$%
$=\frac{9}{10}\times100$%
$=9\times10$%
$=90$%
The first number is 90% of the second number.
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