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The ratio of the corresponding altitudes of two similar triangles is $ \frac{3}{5} $. Is it correct to say that ratio of their areas is $ \frac{6}{5} $ ? Why?
Given:
The ratio of the corresponding altitudes of two similar triangles is \( \frac{3}{5} \).
To do:
We have to find whether the ratio of their areas is \( \frac{6}{5} \).
Solution:
We know that,
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. Therefore,
$\frac{\text { Area of 1st triangle }}{\text { Area of 2nd triangle }}=(\frac{\text { Altitude of 1st triangle }}{\text { Altitude of 2nd triangle }})^2$
$=(\frac{3}{5})^2$
$=\frac{9}{25}$
Therefore,
The ratio of the areas of the given triangles is not equal to \( \frac{6}{5} \).
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