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The lid of a rectangular box of sides $ 40 \mathrm{~cm} $ by $ 10 \mathrm{~cm} $ is sealed all round with tape. What is the length of the tape required?
Given:
The lid of a rectangular box of sides $40 \mathrm{~cm}$ by $10 \mathrm{~cm}$ is sealed all round with tape.
To do:
We have to find the length of the tape required.
Solution:
We know that,
Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$
Tape is sealed around the rectangular box.
Length $=40\ cm$ and breadth $=10\ cm$
Therefore,
The perimeter of the given rectangular box $= 2 (l+b)$
$= 2 (40+10)$
$= 2(50)$
$= 100\ cm$
Therefore the length of the required tape is $100\ cm$.
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