![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
The following table shows the ages of the patients admitted in a hospital during a year:
Age (in years): | 5-15 | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 |
No. of students: | 6 | 11 | 21 | 23 | 14 | 5 |
Find the mode and mean of the data given above. Compare and interpret the two measures of central tendency."
Given:
The ages of the patients admitted in a hospital during a year.
To do:
We have to find the mode and mean of the data given above. Also, we have to compare and interpret the two measures of central tendency.
Solution:
The frequency of the given data is as given below.
We observe that the class interval of 35-45 has the maximum frequency(23).
Therefore, it is the modal class.
Here,
$l=35, h=10, f=23, f_1=21, f_2=14$
We know that,
Mode $=l+\frac{f-f_1}{2 f-f_1-f_2} \times h$
$=35+\frac{23-21}{2 \times 23-21-14} \times 10$
$=35+\frac{2}{46-35} \times 10$
$=35+\frac{20}{11}$
$=35+1.81$
$=36.8$
The mode of the given data is 36.8 years.
We know that,
Mean $=\frac{\sum{f_ix_i}}{\sum{f_i}}$
$=\frac{2830}{80}$
$=35.37$
The mean of the given data is 35.37 years.
Hence, we observe that mean is less than the mode in the given data.