Sum of array using pointer arithmetic in C

In this program, we need to find sum of array elements using pointer arithmetic.

Here we use * which denotes the value stored at the memory address and this address will remain stored in the variable. Thus “int *ptr” means, ptr is a variable which contains an address and content of the address is an integer quantity.

*p means it is a pointer variable. Using this and sum() we will find out sum of the elements of array.

Example Code

#include <stdio.h>
void s(int* a, int len) {
   int i, s_of_arr = 0;
   for (i = 0; i < len; i++)
      s_of_arr = s_of_arr + *(a + i);
   printf( "sum of array is = %d" ,s_of_arr);
}
int main() {
   int arr[] = { 1,2,4,6,7,-5,-3 };
   s(arr, 7);
   return 0;
}

Output

Sum of array = 12

Algorithm

Begin
   Initialize array to hold the variables.
   Call function s to get the sum of the variables.
   Print the sum.
End.

Nitya Raut

Updated on: 30-Jul-2019

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