Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
strtol() function in C++
The strol() function is used to convert the string to long integers. It sets the pointer to point to the first character after the last one. The syntax is like below. This function is present into the cstdlib library.
long int strtol(const char* str, char ** end, int base)
This function takes three arguments. These arguments are like below −
- str: This is the starting of a string.
- str_end: The str_end is set by the function to the next character, after the last valid character, if there is any character, otherwise null.
- base: This specifies the base. The base values can be of (0, 2, 3, …, 35, 36)
This function returns the converted long int. When the character points to NULL, it returns 0.
Example
#include <iostream>
#include<cstdlib>
using namespace std;
main() {
//Define two string
char string1[] = "777HelloWorld";
char string2[] = "565Hello";
char* End; //The end pointer
int base = 10;
int value;
value = strtol(string1, &End, base);
cout << "The string Value = " << string1 << "\n";
cout << "Long Long Int value = " << value << "\n";
cout << "End String = " << End << "\n"; //remaining string after long long integer
value = strtol(string2, &End, base);
cout << "\nThe string Value = " << string2 << "\n";
cout << "Long Long Int value = " << value << "\n";
cout << "End String = " << End; //remaining string after long long integer
}Output
The string Value = 777HelloWorld Long Long Int value = 777 End String = HelloWorld The string Value = 565Hello Long Long Int value = 565 End String = Hello
Now Let us see the example with a different base value. Here the base is 16. By taking the string of given base, it will print in decimal format.
Example
#include <iostream>
#include<cstdlib>
using namespace std;
main() {
//Define two string
char string1[] = "5EHelloWorld";
char string2[] = "125Hello";
char* End; //The end pointer
int base = 16;
int value;
value = strtol(string1, &End, base);
cout << "The string Value = " << string1 << "\n";
cout << "Long Long Int value = " << value << "\n";
cout << "End String = " << End << "\n"; //remaining string after long long integer
value = strtol(string2, &End, base);
cout << "\nThe string Value = " << string2 << "\n";
cout << "Long Long Int value = " << value << "\n";
cout << "End String = " << End; //remaining string after long long integer
}Output
The string Value = 5EHelloWorld Long Long Int value = 94 End String = HelloWorld The string Value = 125Hello Long Long Int value = 293 End String = Hello
Here the string is containing 5E so its value is 94 in decimal, and the second string is containing 125. This is 293 in decimal.
Updated on: 30-Jul-2019
236 Views
Advertisements