Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
String Without AAA or BBB in C++
Suppose we have two integers A and B, we have to return any string S, such that −
S has length A + B and contains exactly A number of letter ‘a’ and B number of ‘b’ letters.
Substring “aaa” and “bbb” will not be in the string S
So if the given integers are A = 4, B = 1, then the result will be “aabaa”.
To solve this, we will follow these steps −
Define a string ret, initially this is empty
while |A – B| >= 2,
if A > B, then
ret := ret concatenate ‘aa’
decrease A by 2
if B is non-zero concatenate ‘b’ with ret and decrease B by 1
else
ret := ret concatenate ‘bb’
decrease B by 2
if A is non-zero concatenate ‘a’ with ret and decrease A by 1
while either A is non-zero, or B is non-zero
if A is non zero and (size of ret < 2 or not of (size of ret >= 2 and last element of ret = second last element of ret) and last element of ret is ‘a’), then
ret := ret + ‘a’, decrease A by 1
if B is non-zero
ret := ret concatenate ‘b’, decrease B by 1
otherwise ret concatenate ‘b’, decrease B by 1, if A is not 0, then concatenate a with ret and decrease A by 1
return ret
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
string strWithout3a3b(int A, int B) {
string ret = "";
while(abs(A - B) >= 2){
if(A > B){
ret += 'a';
ret += 'a';
A -= 2;
if(B) {
ret += 'b';
B--;
}
}else{
ret += 'b';
ret += 'b';
B -= 2;
if(A) {
ret += 'a';
A--;
}
}
}
while(A || B){
if(A && (ret.size() < 2 || !(ret.size() >= 2 && ret[ret.size() - 1] == ret[ret.size() - 2] && ret[ret.size() - 1] == 'a') ) ){
ret += 'a';
A--;
if(B) {
ret += 'b';
B--;
}
}else{
ret += 'b';
B--;
if(A) {
ret += 'a';
A--;
}
}
}
return ret;
}
};
main(){
Solution ob;
cout << (ob.strWithout3a3b(4, 1));
}Input
4 1
Output
"aabaa"
220 Views
