Stack masked arrays in sequence horizontally (column wise) in Numpy

To stack masked arrays in sequence horizontally (column wise), use the ma.hstack() method in Python Numpy. his is equivalent to concatenation along the second axis, except for 1-D arrays where it concatenates along the first axis. Rebuilds arrays divided by hsplit.

This function makes most sense for arrays with up to 3 dimensions. For instance, for pixel-data with a height (first axis), width (second axis), and r/g/b channels (third axis). The functions concatenate, stack and block provide more general stacking and concatenation operations.

The parameters are the arrays that must have the same shape along all but the second axis, except 1-D arrays which can be any length. The function returns the array formed by stacking the given arrays. It is applied to both the _data and the _mask, if any.

Steps

At first, import the required library −

import numpy as np
import numpy.ma as ma

Create Array 1, a 3x3 array with int elements using the numpy.arange() method −

arr1 = np.arange(9).reshape((3,3))
print("Array1...
", arr1) print("\nArray type...
", arr1.dtype)

Create a masked array1 −

arr1 = ma.array(arr1)

Mask Array1

arr1[0, 1] = ma.masked
arr1[1, 1] = ma.masked

Display Masked Array1 −

print("\nMasked Array1...
",arr1)

Create Array 2, another 3x3 array with int elements using the numpy.arange() method −

arr2 = np.arange(9).reshape((3,3))
print("\nArray2...
", arr2) print("\nArray type...
", arr2.dtype)

Create masked array2 −

arr2 = ma.array(arr2)

Mask Array2 −

arr2[2, 1] = ma.masked
arr2[2, 2] = ma.masked

Display Masked Array 2 −

print("\nMasked Array2...
",arr2)

To stack masked arrays in sequence horizontally (column wise), use the ma.hstack() method in Python Numpy:

print("\nResult of stacking arrays horizontally...
",ma.hstack((arr1, arr2)))

Example

# Python ma.MaskedArray - Stack masked arrays in sequence horizontally (column wise)

import numpy as np
import numpy.ma as ma

# Array 1
# Creating a 3x3 array with int elements using the numpy.arange() method
arr1 = np.arange(9).reshape((3,3))
print("Array1...
", arr1) print("\nArray type...
", arr1.dtype) # Get the dimensions of the Array print("\nArray Dimensions...
",arr1.ndim) # Get the shape of the Array print("\nOur Array Shape...
",arr1.shape) # Get the number of elements of the Array print("\nElements in the Array...
",arr1.size) # Create a masked array arr1 = ma.array(arr1) # Mask Array1 arr1[0, 1] = ma.masked arr1[1, 1] = ma.masked # Display Masked Array 1 print("\nMasked Array1...
",arr1) # Array 2 # Creating another 3x3 array with int elements using the numpy.arange() method arr2 = np.arange(9).reshape((3,3)) print("\nArray2...
", arr2) print("\nArray type...
", arr2.dtype) # Get the dimensions of the Array print("\nArray Dimensions...
",arr2.ndim) # Get the shape of the Array print("\nOur Array Shape...
",arr2.shape) # Get the number of elements of the Array print("\nElements in the Array...
",arr2.size) # Create a masked array arr2 = ma.array(arr2) # Mask Array2 arr2[2, 1] = ma.masked arr2[2, 2] = ma.masked # Display Masked Array 2 print("\nMasked Array2...
",arr2) # To stack masked arrays in sequence horizontally (column wise), use the ma.hstack() method in Python Numpy print("\nResult of stacking arrays horizontally...
",ma.hstack((arr1, arr2)))

Output

Array1...
[[0 1 2]
[3 4 5]
[6 7 8]]

Array type...
int64

Array Dimensions...
2

Our Array Shape...
(3, 3)

Elements in the Array...
9

Masked Array1...
[[0 -- 2]
[3 -- 5]
[6 7 8]]

Array2...
[[0 1 2]
[3 4 5]
[6 7 8]]

Array type...
int64

Array Dimensions...
2

Our Array Shape...
(3, 3)

Elements in the Array...
9

Masked Array2...
[[0 1 2]
[3 4 5]
[6 -- --]]

Result of stacking arrays horizontally...
[[0 -- 2 0 1 2]
[3 -- 5 3 4 5]
[6 7 8 6 -- --]]
Updated on: 2022-02-03T12:33:05+05:30

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