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Sorting an array object by property having falsy value - JavaScript
Suppose, we have an array of objects like this −
const array = [
{key: 'a', value: false},
{key: 'a', value: 100},
{key: 'a', value: null},
{key: 'a', value: 23}
];We are required to write a JavaScript function that takes in one such array and places all the objects that have falsy values for the "value" property to the bottom and sorts all other objects in decreasing order by the "value" property.
Example
Following is the code −
const arr = [
{key: 'a', value: false},
{key: 'a', value: 100},
{key: 'a', value: null},
{key: 'a', value: 23}
];
const isValFalsy = (obj) => !obj.value && typeof obj.value !== 'number';
const sortFalsy = arr => {
arr.sort((a, b) => {
if(isValFalsy(a) && isValFalsy(b)){
return 0;
}
if(isValFalsy(a)){
return 1;
};
if(isValFalsy(b)){
return -1;
};
return b.value - a.value;
});
};
sortFalsy(arr);
console.log(arr);Output
This will produce the following output in console −
[
{ key: 'a', value: 100 },
{ key: 'a', value: 23 },
{ key: 'a', value: false },
{ key: 'a', value: null }
]
Updated on: 30-Sep-2020
141 Views
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