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Solve the following linear equation.
$ \frac{n}{2}-\frac{3 n}{4}+\frac{5 n}{6}=21 $.
Given:
$\frac{n}{2}-\frac{3 n}{4}+\frac{5 n}{6}=21$.
To do:
We have to solve the given linear equation.
Solution:
$\frac{n}{2}-\frac{3 n}{4}+\frac{5 n}{6}=21$
This implies,
$\frac{n(6) - 3n( 3) +5n(2)}{12}=21$
$\frac{6n - 9n + 10n}{12} = 21$
$\frac{7n}{12}= 21$
$n =21 \times \frac{12}{7}$
$n =3 \times 12$
$n = 36$
The value of $n$ is $36$.
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