Solve the following equations.
$ \frac{z}{z+15}=\frac{4}{9} $.
Given:
\( \frac{z}{z+15}=\frac{4}{9} \)
To do:
We have to solve the given equation.
Solution:
$\frac{z}{z+15}=\frac{4}{9}$
$\Rightarrow 9(z)=4 \times(z+15)$ [On cross multiplication]
$\Rightarrow 9z=4z+60$
$\Rightarrow 9z-4z=60$
$\Rightarrow 5z=60$
$\Rightarrow z=\frac{60}{5}$
$\Rightarrow z=12$
The value of $z$ is $12$.
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