Solve the following equations.
$ \frac{7 y+4}{y+2}=\frac{-4}{3} $.

Given:

\( \frac{7 y+4}{y+2}=\frac{-4}{3} \)

To do: 

We have to solve the given equation.

Solution:

$\frac{7 y+4}{y+2}=\frac{-4}{3}$

$\Rightarrow 3(7y+4)=(-4) \times(y+2)$                [On cross multiplication]

$\Rightarrow 21y+12=-4y-8$

$\Rightarrow 21y+4y=-8-12$

$\Rightarrow 25y=-20$

$\Rightarrow y=\frac{-20}{25}$

$\Rightarrow y=\frac{-4}{5}$

The value of $y$ is $\frac{-4}{5}$. 

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Updated on: 10-Oct-2022

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