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Solve the following equations.
\( \frac{3 y+4}{2-6 y}=\frac{-2}{5} \).
Given:
\( \frac{3 y+4}{2-6 y}=\frac{-2}{5} \)
To do:
We have to solve the given equation.
Solution:
$\frac{3 y+4}{2-6 y}=\frac{-2}{5}$
$\Rightarrow 5(3y+4)=(-2) \times(2-6y)$ [On cross multiplication]
$\Rightarrow 15y+20=-4+12y$
$\Rightarrow 15y-12y=-4-20$
$\Rightarrow 3y=-24$
$\Rightarrow y=\frac{-24}{3}$
$\Rightarrow y=-8$
The value of $y$ is $-8$.
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