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Solve the following equations and check your results.
$ 2 y+\frac{5}{3}=\frac{26}{3}-y $.
Given:
\( 2 y+\frac{5}{3}=\frac{26}{3}-y \)
To do:
We have to solve the given equation and check the result.
Solution:
$2 y+\frac{5}{3}=\frac{26}{3}-y$
$2y+y=\frac{26}{3}-\frac{5}{3}$
$3y=\frac{26-5}{3}$
$3y=\frac{21}{3}$
$3y=7$
$y=\frac{7}{3}$
Substituting the value of $y$ in LHS, we get,
$2y+\frac{5}{3}=2(\frac{7}{3})+\frac{5}{3}$
$=\frac{14}{3}+\frac{5}{3}$
$=\frac{14+5}{3}$
$=\frac{19}{3}$
Substituting the value of $y$ in RHS, we get,
$\frac{26}{3}-y=\frac{26}{3}-\frac{7}{3}$
$=\frac{26-7}{3}$
$=\frac{19}{3}$
LHS $=$ RHS
The value of $y$ is $\frac{7}{3}$.
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