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set operator= in C++ STL
The function operator= is used in sets to copy one set (or move to another in C++ STL. It behaves as a normal ‘=’ assignment operation for sets. There are there overloaded forms of this function −
copy :- set& operator= (const set& s1) −
This function copies all the elements in set s1 to another set. The parameter passed is set of the same type.
Usage − set s1=s2;
move :- set& operator=( set &&s1 ) −
This moves the elements of set s1 into the calling set.
Initializer list :- set& operator= (initializer_list<value_type> ilist) −
This version copies the values of the initializer list ilist into the calling set.
Usage − set<int> s1= { 1,2,3,4,5 };
Note − All of them return the reference of this pointer of set<T> type.
Following program is used to demonstrate the usage of round function in a C++ program −
Example
#include <iostream>
#include <set>
using namespace std;
// merge function
int main(){
set<int> set1, set2;
// List initialization
set1 = { 1, 2, 3, 4, 5 };
set2 = { 10,11,12,13 };
// before copy
cout<<"set1 :";
for (auto s = set1.begin(); s != set1.end(); ++s) {
cout << *s << " ";
}
cout << endl;
cout<<"set2 :";
for (auto s = set2.begin(); s != set2.end(); ++s) {
cout << *s << " ";
}
//after copy set1 to set2
cout<<endl<<"After Copy"<<endl;
cout<<"set1 :";
set1=set2;
for (auto s = set1.begin(); s != set1.end(); ++s) {
cout << *s << " ";
}
return 0;
}Output
set1 :1 2 3 4 5 set2 :10 11 12 13 After Copy set1 :10 11 12 13
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