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Select count of values (Yes, No) with same ids but different corresponding records in MySQL?
For this, you can use SUM() along with CASE statement. Let us first create a −
mysql> create table DemoTable1430
-> (
-> EmployeeId int,
-> isMarried ENUM('YES','NO')
-> );
Query OK, 0 rows affected (0.60 sec)Insert some records in the table using insert −
mysql> insert into DemoTable1430 values(1001,'Yes'); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable1430 values(1001,'No'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable1430 values(1001,'Yes'); Query OK, 1 row affected (0.09 sec) mysql> insert into DemoTable1430 values(1001,'Yes'); Query OK, 1 row affected (0.16 sec)
Display all records from the table using select −
mysql> select * from DemoTable1430;
This will produce the following output −
+------------+-----------+ | EmployeeId | isMarried | +------------+-----------+ | 1001 | YES | | 1001 | NO | | 1001 | YES | | 1001 | YES | +------------+-----------+ 4 rows in set (0.00 sec)
Here is the query to select count of value (Yes, No) −
mysql> select EmployeeId,sum(isMarried='Yes') as NumberOfMarried, -> sum(isMarried='No') as NumberOfUnMarried -> from DemoTable1430 -> group by EmployeeId;
This will produce the following output −
+------------+-----------------+-------------------+ | EmployeeId | NumberOfMarried | NumberOfUnMarried | +------------+-----------------+-------------------+ | 1001 | 3 | 1 | +------------+-----------------+-------------------+ 1 row in set (0.00 sec)
Updated on: 12-Nov-2019
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