Replace \( \square \) in each of the following by the correct number:
(a) \( \frac{2}{7}=\frac{8}{\square} \)
(b) \( \frac{5}{8}=\frac{10}{\square} \)
(c) \( \frac{3}{5}=\frac{\square}{20} \)
(d) \( \frac{45}{60}=\frac{15}{\square} \)
(e) \( \frac{18}{24}=\frac{\square}{4} \)
To do:
We have to replace \( \square \) by the correct numbers.
Solution:
(a) Let $x$ be the number in the square.
Therefore,
$\frac{2}{7}=\frac{8}{x}$
On cross multiplication, we get,
$2\times x=7\times8$
$x=\frac{7\times8}{2}$
$x=7\times4$
$x=28$
The required number is 28.
(b) Let $x$ be the number in the square.
Therefore,
$\frac{5}{8}=\frac{10}{x}$
On cross multiplication, we get,
$5\times x=10\times8$
$x=\frac{10\times8}{5}$
$x=2\times8$
$x=16$
The required number is 16.
(c) Let $x$ be the number in the square.
Therefore,
$\frac{3}{5}=\frac{x}{20}$
On cross multiplication, we get,
$3\times 20=x\times5$
$x=\frac{3\times20}{5}$
$x=3\times4$
$x=12$
The required number is 12.
(d) Let $x$ be the number in the square.
Therefore,
$\frac{45}{60}=\frac{15}{x}$
On cross multiplication, we get,
$45\times x=15\times60$
$x=\frac{15\times60}{45}$
$x=\frac{60}{3}$
$x=20$
The required number is 20.
(e) Let $x$ be the number in the square.
Therefore,
$\frac{18}{24}=\frac{x}{4}$
On cross multiplication, we get,
$18\times 4=x \times24$
$x=\frac{18\times4}{24}$
$x=\frac{18}{6}$
$x=3$
The required number is 3.
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