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Regular Expression "S" Metacharacter in Java
The subexpression/metacharacter “\S” matches the non-white space characters.
Example 1
import java.util.regex.Matcher; import java.util.regex.Pattern; public class RegexExample { public static void main( String args[] ) { String regex = "\S"; String input = "Hello how are you welcome to Tutorialspoint !"; Pattern p = Pattern.compile(regex); Matcher m = p.matcher(input); int count = 0; while(m.find()) { count++; } System.out.println("Number of matches: "+count); } }
Output
Number of matches: 38
Example 2
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example { public static void main( String args[] ) { String regex = "\S"; Scanner sc = new Scanner(System.in); System.out.println("Enter 5 input strings: "); String input[] = new String[5]; for (int i=0; i<5; i++) { input[i] = sc.nextLine(); } //Creating a Pattern object Pattern p = Pattern.compile(regex); System.out.println("Number of characters in each string w/o spaces: "); for(int i=0; i<5;i++) { //Creating a Matcher object Matcher m = p.matcher(input[i]); int count = 0; while(m.find()) { count++; } System.out.println("String "+i+": "+count); } } }
Output
Enter 5 input strings: sample123 test data test *123 ab bc cd de hello how are you welcome to Tutorialspoint Number of characters in each string w/o spaces: String 0: 9 String 1: 8 String 2: 8 String 3: 8 String 4: 37
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