Reduce the following fractions to simplest form:
(a) $ \frac{48}{60} $
(b) $ \frac{150}{60} $
(c) $ \frac{84}{98} $
(d) $ \frac{12}{52} $
(e) $ \frac{7}{28} $
To do:
We have to reduce the given fractions to their simplest forms.
Solution :
(a) $\frac{48}{60}$
$\frac{48}{60}= \frac{12\times4}{12\times5}$
$= \frac{4}{5}$
Therefore, $\frac{4}{5}$ is the simplest form of $\frac{48}{60}$.
(b) $\frac{150}{60}$
$\frac{150}{60}= \frac{30\times5}{30\times2}$
$= \frac{5}{2}$
Therefore, $\frac{5}{2}$ is the simplest form of $\frac{150}{60}$.
(c) $\frac{84}{98}$
$\frac{84}{98}= \frac{14\times6}{14\times7}$
$= \frac{6}{7}$
Therefore, $\frac{6}{7}$ is the simplest form of $\frac{84}{98}$.
(d) $\frac{12}{52}$
$\frac{12}{52}= \frac{4\times3}{4\times13}$
$= \frac{3}{13}$
Therefore, $\frac{3}{13}$ is the simplest form of $\frac{12}{52}$.
(e) $\frac{7}{28}$
$\frac{7}{28}= \frac{7\times1}{7\times4}$
$= \frac{1}{4}$
Therefore, $\frac{1}{4}$ is the simplest form of $\frac{7}{28}$.
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