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Python – Check if elements index are equal for list elements
When it is required to check if the index of the elements is equal to the elements in the list, a simple iteration and the enumerate attribute is used.
Example
Below is a demonstration of the same −
my_list_1 = [12, 62, 19, 79, 58, 0, 99]
my_list_2 = [12, 74, 19, 54, 58, 0, 11]
print("The first list is :")
print(my_list_1)
print("The second list is :")
print(my_list_2)
my_list_1.sort()
my_list_2.sort()
print("The first list after sorting is ")
print(my_list_1)
print("The second list after sorting is ")
print(my_list_2)
check_list = [9, 8, 2]
print("The check_list is :")
print(check_list)
my_result = True
for index, element in enumerate(my_list_1):
if my_list_1[index] != my_list_2[index] and element in check_list:
my_result = False
break
print("The result is :")
if(my_result == True):
print("The index elements is equal to the elements of the list")
else:
print("The index elements is not equal to the elements of the list")Output
The first list is : [12, 62, 19, 79, 58, 0, 99] The second list is : [12, 74, 19, 54, 58, 0, 11] The first list after sorting is [0, 12, 19, 58, 62, 79, 99] The second list after sorting is [0, 11, 12, 19, 54, 58, 74] The check_list is : [9, 8, 2] The result is : The index elements is equal to the elements of the list
Explanation
Two lists of integers are defined and are displayed on the console.
They are sorted and displayed on the console.
Another list of integers is defined and is displayed on the console.
A value is set to Boolean True.
The first list is iterated over using enumerate and the index of the first two elements of the two respective lists are compared.
If they are equal and if this element is present in the list of integers, the Boolean value is set to False.
The control breaks out of the loop.
Based on the Boolean value, relevant message is displayed on the console.
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