![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Program to form smallest number where no two adjacent digits are same in Python
Suppose we have a string s with four possible characters "1", "2", "3" and "?". We can place any one of "1", "2" and "3", in the place of "?". We have to find the smallest possible number that we can make such that no two adjacent digits are same.
So, if the input is like s = "2??3?", then the output will be 21231
To solve this, we will follow these steps −
- i := 0
- s := a list of elements from s
- if size of s < 2, then
- if s[i] is same as "?", then
- return "1"
- if s[i] is same as "?", then
- while i < size of s, do
- if s[i] is same as "?", then
- if i is same as 0, then
- s[i] := "1" when s[i + 1] is not "1" otherwise "2"
- otherwise when i > 0 and i <= size of s - 2, then
- if s[i - 1] is same as "1", then
- if s[i + 1] is same as "2", then
- s[i] := "3"
- otherwise,
- s[i] := "2"
- if s[i + 1] is same as "2", then
- otherwise when s[i - 1] is same as "2", then
- if s[i + 1] is same as "2", then
- s[i] := "3"
- otherwise,
- s[i] := "1"
- if s[i + 1] is same as "2", then
- otherwise when s[i - 1] is same as "3", then
- if s[i + 1] is same as "2", then
- s[i] := "2"
- otherwise,
- s[i] := "1"
- if s[i + 1] is same as "2", then
- if s[i - 1] is same as "1", then
- otherwise,
- s[i] := "1" when s[i - 1] is not "1" otherwise "2"
- if i is same as 0, then
- i := i + 1
- if s[i] is same as "?", then
- join items of s into a string and return
Example
Let us see the following implementation to get better understanding −
def solve(s): i = 0 s = list(s) if len(s) < 2: if s[i] == "?": return "1" while i < len(s): if s[i] == "?": if i == 0: s[i] = "1" if s[i + 1] != "1" else "2" elif i > 0 and i <= len(s) - 2: if s[i - 1] == "1": if s[i + 1] == "2": s[i] = "3" else: s[i] = "2" elif s[i - 1] == "2": if s[i + 1] == "1": s[i] = "3" else: s[i] = "1" elif s[i - 1] == "3": if s[i + 1] == "1": s[i] = "2" else: s[i] = "1" else: s[i] = "1" if s[i - 1] != "1" else "2" i += 1 return "".join(s) s = "2??3?" print(solve(s))
Input
"2??3?"
Output
21231
Advertisements