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Program to find the head start in a race in C++
In this problem, we are given two integers that give the head start that is given by A to B and C respectively in a 100-meter race. Our task is to create a program to find the head start in a race in C++.
Code Description − Here, there are head starts that are given by A to B and A to C respectively in a 100-meter race. We need to find the relative head start that is given by B to C in the 100-meter race.
Let’s take an example to understand the problem,
Input
20, 28
Output
90
Explanation
A gives B a head-start of 15 i.e. if A completes 100 m, then B completes 80.
A gives C a head-start of 28 i.e. if A completes 100 m, then B completes 72.
Now, when B completes 80 meters, C completes 72.
If B completes 100, C completed
(72 * 100) / 80 = 90
Solution Approach
To solve the problem, find the distance that B and C complete when A completes 100 meters. After this we calculate the distance that C completes when B completes 100, using the formula −
(C * 100) B
Program to illustrate the working of our solution,
Example
#include <iostream>
using namespace std;
int CalcHeadStart(int B, int C) {
return ( 100 - ( ( (100 - C)*100 ) / (100 - B)) ) ;
}
int main() {
int B = 12, C = 34;
cout<<"Head start in a race by B to C is "<<CalcHeadStart(B, C) << " meters";
return 0;
}Output
Head start in a race by B to C is 25 meters
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