Program to check two rectangular overlaps or not in Python

Suppose we have a rectangle that is represented as a list with four elements [x1, y1, x2, y2], where (x1, y1) is the coordinates of its bottom-left corner, and (x2, y2) is the coordinates of its top-right corner. Two rectangles overlap when the area of their intersection is positive. So, two rectangles that only touch at the corner or edges do not overlap.

So, if the input is like R1 = [0,0,2,2], R2 = [1,1,3,3], then the output will be True.

To solve this, we will follow these steps −

• if R1[0]>=R2[2] or R1[2]<=R2[0] or R1[3]<=R2[1] or R1[1]>=R2[3], then
  • return False
• otherwise,
  • return True

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, R1, R2):
      if (R1[0]>=R2[2]) or (R1[2]<=R2[0]) or (R1[3]<=R2[1]) or (R1[1]>=R2[3]):
         return False
      else:
         return True
ob = Solution()
print(ob.solve([0,0,3,3],[1,1,4,4]))

Input

[0,0,3,3],[1,1,4,4]

Output

True

Arnab Chakraborty

Updated on: 07-Oct-2020

3K+ Views

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