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Program find number of subsets of colorful vertices that meets given conditions in Python
Given an array colors representing colors for vertices of a regular n-gon polygon, we need to find the number of special subsets that meet specific conditions. Each vertex is randomly colored with one of n different colors.
Problem Conditions
A special subset must satisfy these requirements:
- The subset size must be at least two
- When we remove vertices in the subset (and their adjacent edges), the remaining vertices form continuous paths
- None of these paths should contain two vertices of the same color
If the answer is large, return the result modulo 10^9 + 7.
Algorithm Approach
The solution follows these steps:
- Create a map to group vertices by their colors
- Calculate total possible subsets of size ? 2
- Subtract invalid subsets where same-colored vertices would be adjacent in remaining paths
Implementation
from collections import defaultdict
from math import factorial
def nCr(n, i):
if n == 1 or i == 0 or i == n:
return 1
return factorial(n) // factorial(i) // factorial(n - i)
def solve(colors):
count = defaultdict(list)
n = len(colors)
# Group vertices by color
for i in range(len(colors)):
count[colors[i]].append(i)
answer = 0
# Calculate total subsets of size >= 2
for i in range(2, n + 1):
answer += nCr(n, i)
# Subtract invalid subsets
for color in count.keys():
vertices = count[color]
n_vertices = len(vertices)
if n_vertices > 1:
for i in range(n_vertices - 1):
for j in range(i + 1, n_vertices):
# Calculate distances between same-colored vertices
d1 = vertices[j] - vertices[i]
d2 = vertices[i] - vertices[j] + n
# If vertices are too close, they would violate conditions
if d1 <= n - 3 or d2 <= n - 3:
answer -= 1
return answer
# Test the function
colors = [1, 2, 3, 4]
result = solve(colors)
print(f"Number of special subsets: {result}")
Number of special subsets: 11
How It Works
For the example colors = [1, 2, 3, 4]:
- Each vertex has a unique color, so no same-colored vertices exist
- Total subsets of size ? 2: C(4,2) + C(4,3) + C(4,4) = 6 + 4 + 1 = 11
- No invalid subsets to subtract since all colors are different
- Final answer: 11
Key Points
- The algorithm uses combinatorics to count valid subsets efficiently
- Same-colored vertices that are too close in the polygon create invalid configurations
- Distance calculation considers the circular nature of the polygon
Conclusion
This solution efficiently counts special subsets by calculating total possibilities and subtracting invalid cases. The time complexity is O(n²) in the worst case when many vertices share the same color.
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