Article Categories
- All Categories
-
Data Structure
-
Networking
-
RDBMS
-
Operating System
-
Java
-
MS Excel
-
iOS
-
HTML
-
CSS
-
Android
-
Python
-
C Programming
-
C++
-
C#
-
MongoDB
-
MySQL
-
Javascript
-
PHP
Selected Reading
Print n smallest elements from given array in their original order
Given with array of let’s say k elements the program must find the n smallest elements amongst them in their appearing order.
Input : arr[] = {1, 2, 4, 3, 6, 7, 8}, k=3
Ouput : 1, 2, 3
Input k is 3 it means 3 shortest elements among the set needs to be displayed in original order like 1 than 2 and than 3
Algorithm
START Step 1 -> start variables as int i, max, pos, j, k=4 and size for array size Step 2 -> Loop For i=k and i=0 and j-- If arr[j]>max Set max = arr[j] Set pos = j End End IF max> arr[i] Set j = pos Loop While j Loop For i = 0 and i Example
#includeint main() { int arr[] = {5,8,3,1,2,9}; int i, max, pos, j, k=4; int size = sizeof(arr)/sizeof(arr[0]); //Using insertion sort, Starting from k. for(i=k;i =0;j--) { if(arr[j]>max) { max = arr[j]; pos = j; } } if ( max> arr[i] ) { j = pos; while( j Output
if we run above program then it will generate following output.
5 3 1 2
Advertisements
