You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of:

(a) potassium chloride  (b) potassium nitride  (c) potassium sulphide  (d) potassium iodide

Correct Answer: (d) potassium iodide
 

Explanation: Potassium iodide reacts with lead nitrate to give a yellow ppt. of lead iodide.

$2KI\ ( aq) \ +\ Pb( NO_{3})_{2\ }( aq) \ \rightarrow \ PbI_{2} \ ( s) \ +\ 2KNO_{3} \ ( aq)$

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Updated on: 10-Oct-2022

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