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Write the molecular formula of the 2nd and 3rd members of the homologous series where the first member is ethyne.
The molecular formula of the 2nd and 3rd members of a homologous series where the first member is ethyne (C2H2) is formed by adding -CH2-
2nd member = propyne (C3H4) CH3 - CH2 - C º CH
3rd member = butyne (C4H6) CH3 - CH2 - C º CH
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